我试图说服一个Toggle按钮在单击“Start Timer”时启动Timer1和Timer2并且只停止Timer1使Timer2继续“Stop Timer” 我的主要活动看起来像这样:
StoredProcedureQuery storedProcedureQuery = entityManagerFactory.createEntityManager().createStoredProcedureQuery("ModelSearchByModel",ModelSearchByModelEntity.class);
storedProcedureQuery.registerStoredProcedureParameter("RegionCode", String.class , ParameterMode.IN);
// register all the other parameters...
storedProcedureQuery.setParameter("RegionCode", regionCode);
// set all the other parameters...
return storedProcedureQuery.execute() ? storedProcedureQuery.getResultList() : null;
目标是当切换“START TIMER”时,单击TIMERS(chrononeter1和chronometer2)应该启动,当点击“STOP TIMER”时,只有chronometer1应该停止。 请指教!谢谢!
XML看起来像这样:
public class MainActivity extends AppCompatActivity {
long init, now, paused, millis, seconds, minutes, hours;
TextView display;
TextView display2;
Handler handler;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
handler = new Handler();
display = (TextView) findViewById(R.id.chronometer1);
final ToggleButton passTog = (ToggleButton) findViewById(R.id.toggleButton1);
final Runnable updater = new Runnable() {
@Override
public void run() {
if (passTog.isChecked()) {
now = System.currentTimeMillis();
millis = now - init;
seconds = ((millis / 1000) % 60);
minutes = (millis / 1000) / 60;
hours = (minutes / 3600000);
String hh = hours < 10 ? "0" + hours : hours + "";
String mm = minutes < 10 ? "0" + minutes : minutes + "";
String ss = seconds < 10 ? "0" + seconds : seconds + "";
display.setText(hh + ":" + mm + ":" + ss);
handler.postDelayed(this, 10);
continueTimer();
}
}
};
passTog.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
init = System.currentTimeMillis();
handler.post(updater);
}
});
}
@Override
protected void onPause() {
super.onPause();
paused = System.currentTimeMillis();
}
@Override
protected void onResume() {
super.onResume();
init += System.currentTimeMillis() - paused;
}
public void continueTimer() {
display2 = (TextView) findViewById(R.id.chronometer2);
now = System.currentTimeMillis();
millis = now - init;
seconds = ((millis / 1000) % 60);
minutes = (millis / 1000) / 60;
hours = (minutes / 3600000);
String hh = hours < 10 ? "0" + hours : hours + "";
String mm = minutes < 10 ? "0" + minutes : minutes + "";
String ss = seconds < 10 ? "0" + seconds : seconds + "";
display2.setText(hh + ":" + mm + ":" + ss);
}
答案 0 :(得分:1)
好的,一直看着你的代码。你可以使用天文台表。 像:
//Decalare and initialize timer1.
private Chronometer timer1;
timer1 = (Chronometer)v.findViewById(R.id.chronometer1);
//Declare and initialize timer2.
private Chronometer timer2;
timer2 =(Chronometer)v.findViewById(R.id.chronometer2);
然后在切换按钮中启动它们:
@Override
public void run() {
if (passTog.isChecked()) {
//start chronometers
timer1.start();
timer2.start();
}
然后当passTog.isChecked()= false时,只调用timer1.stop()。第二个计时器将继续。
换句话说,当检查切换时,在两个计时器上调用.start(),并且当取消选中切换时,只在一个计时器上调用.stop()。
我没有看到&#34;停止计时器&#34;代码。