Reactive Banana 1.0.0 - MomentIO中的单元测试()Monad

时间:2015-11-09 15:59:48

标签: unit-testing haskell reactive-banana

这是我用来调查特定monadic动作行为的事件网络示例。我想要一种原则性的方法,而不是这种测试我的代码的特殊方式。我知道如何测试我的功能,但我正在寻找测试行为和事件的最佳实践,考虑到reactive-banana 1.0.0

中的新设计选择

我遗漏了很多,希望我只包括说明问题的必要条件。请告诉我是否应该包含哪些内容,以使问题更加清晰。

makeNetworkDescription ::  Parameters -> MomentIO ()
makeNetworkDescription params = mdo
  eInput <- fromAddHandler (input params)
  eTick <- fromAddHandler (tick params)
  let   
   eValidated :: Event VAC
   eValidated = toVAC <$> eInput

   eClearBuffer = Clear <$ eBuffer

   eBuffer ::Event BufferMap
   eBuffer = bBuffer <@ eTick

  bBuffer <- accumB (BufferMap (M.empty :: M.Map AID VAC))  $
             manageBuffer <$> unionWith (clearBuffer) eValidated eClearBuffer    
 reactimate $ writeOut_Debug <$> eBuffer

缓冲区应该做什么,是累积的​​播放器命令(然后在其他地方处理),然后在处理完一批特定的播放器命令后清空。在下一次打勾时,它会再次发生。

我正在寻求确保缓冲区在它应该被清除时被清除,并且累积像它应该的命令。现在,代码有效,我想编写测试以确保它在我构建这个游戏时继续工作。

我可以在上面的示例中将缓冲区BehaviorEvent网络分开,但那又是什么呢?从测试中获得准确结果的最佳方法是什么?

修改:更新 - 我相信this link会提供足够的提示。我明天会对它进行一次尝试并详细报告。

编辑:更新 - 我写了一个单元测试。我会上传到github,当它是purty,然后发布。以上链接非常有助于理清该做什么。

编辑:更新 - 结果,如果你运行堆栈测试并且存在类型错误,然后再次运行它会得到输出,说明你的测试已通过。结果是,我和昨天的关系并不紧密。我有代码和更清晰的问题。我可以为那个开始一个不同的帖子。

编辑:更新 - 我的测试以一种有用的方式打破,但我不知道该怎么做。我已经发布了整个project的上下文。下面我只包括测试代码,错误和一些讨论。

main :: IO ()
main = defaultMain
  [ testGroup "EventNetwork Input"
    [testBuffer "bBuffer" Populated]
  ]

testBuffer :: String -> BufferState -> Test
testBuffer name Populated =
testCase name $ assert $ bufferPopulated (UAC (PlayerCommand (Move   (ToPlanetName Mongo)) (AID (Data.Text.pack "100"))))
testBuffer name Empty =
testCase name $ assert $ bufferEmptied (UAC (PlayerCommand (Move    (ToPlanetName Mongo)) (AID (Data.Text.pack "100"))))

bufferPopulated :: UAC -> MomentIO Bool
bufferPopulated ev = do
  let eInput = ev <$ never
      eValidated = toVAC <$> eInput
  bBufferMap <- (buffer eValidated eClear) :: MomentIO (Behavior BufferMap)
  let r2 = [(Just $ BufferMap $ M.insert (AID (Data.Text.pack "100")) (toVAC ev) (M.empty :: M.Map AID VAC))]
r1 <- liftIO $ ((interpret (eBuffer bBufferMap) []) :: IO [Maybe BufferMap])
return $ r1 == r2

bufferEmptied :: UAC -> MomentIO Bool
bufferEmptied ev = undefined

eBuffer :: Behavior BufferMap -> Event a -> Event BufferMap
eBuffer bBufferMap nvr =
  bBufferMap <@ (() <$ nvr)

eClear = Clear <$ (() <$ never)


tests/Spec.hs:26:19:
    No instance for (Test.HUnit.Base.Assertable (MomentIO Bool))
      arising from a use of ‘assert’
In the expression: assert
In the second argument of ‘($)’, namely
  ‘assert
   $ bufferPopulated
       (UAC
          (PlayerCommand (Move (ToPlanetName Mongo)) (AID (pack "100"))))’
In the expression:
  testCase name
  $ assert
    $ bufferPopulated
        (UAC
           (PlayerCommand (Move (ToPlanetName Mongo)) (AID (pack "100"))))

问题归结为accumBBehavior中创建MomemtIO。如果我bufferPopulated返回IO Bool,我该如何协调?

编辑:显而易见的是编写它想要的实例。我想这可能是一个红鲱鱼。你怎么看。这只是编写MomentIO Bool实例吗?

编辑:更新 我想我走在正确的轨道上。我已经注释掉了所有测试工具代码并更改了bufferPopulated

的签名
bufferPopulated :: UAC -> IO Bool
bufferPopulated ev = do
  let eInput = ev <$ never
      eValidated = toVAC <$> eInput
  bBufferMap <- liftMoment ((buffer eValidated eClear) :: Moment    (Behavior BufferMap)) 
  let r2 = [(Just $ BufferMap $ M.insert (AID (Data.Text.pack "100")) (toVAC ev) (M.empty :: M.Map AID VAC))]
  r1 <- (interpret (eBuffer bBufferMap) []) :: IO [Maybe BufferMap])          
  return $ r1 == r2

我相信这应该有用,但这是错误

tests/Spec.hs:35:17:
    No instance for (MonadMoment IO) arising from a use of ‘liftMoment’
    In a stmt of a 'do' block:
      bBufferMap <- liftMoment
                      ((buffer eValidated eClear) :: Moment (Behavior   BufferMap))

我们来看看MonadMoment

中的Reactive.Banana.Combinators
class Monad m => MonadMoment m where

An instance of the MonadMoment class denotes a computation that happens at one particular moment in time.

Unlike the Moment monad, it need not be pure anymore.

Methods

liftMoment :: Moment a -> m a

Instances
MonadMoment MomentIO
MonadMoment Moment  

m可以是MonadIOMonad。所以liftMoment应该将Moment Behavior (BufferMap)提升为IO Behavior (BufferMap),为什么不呢。我的推理出了什么问题?

1 个答案:

答案 0 :(得分:1)

答案的来源来自之前的答案。

Testing in reactive-banana

interpretFramwork需要新的签名。

interpretFrameWorks'' :: (Event a -> MomentIO (Behavior b)) -> [a] ->  IO (b,[[b]])
interpretFrameWorks'' f xs = do
  output                      <- newIORef []
  init                        <- newIORef undefined
  (addHandler, runHandlers)   <- newAddHandler
  network                     <- compile $ do
    e <- fromAddHandler addHandler
    f' <- f e
    o <- changes $ f'
    i <- valueB $ f'
    liftIO $ writeIORef init i
    reactimate' $ (fmap . fmap) (\b -> modifyIORef output (++[b])) o

  actuate network
  bs <- forM xs $ \x -> do
      runHandlers x
      bs <- readIORef output
      writeIORef output []
      return bs
  i <- readIORef init
  return (i, bs)