Question

Xcode 7.1 - swift2.0 - parse.com

收到错误：

模糊地使用'url'

if let AudioFileURLTemp = object?.valueForKey("SongFile")?.url {  

           player = AVPlayer(URL: NSURL(string: AudioFileURLTemp!))
        player.play()

        }

请告知

Answer 1

无需使用NSURL或字符串转换。直接访问PFFile网址

if let songFile: PFFile = object?.valueForKey("SongFile") as? PFFile {
    player = AVPlayer(URL: songFile.url!)
    player.play()
}

Answer 2

感谢您的帮助，这是我用于swift 2的功能

func GetSongFromParse（）{

    let querySongs = PFQuery(className: "Songs")
    querySongs.findObjectsInBackgroundWithBlock { (objects, error) -> Void in

        if let objects = objects{

            for object in objects{

                self.iDArray.append(object.valueForKey("objectId") as! String)
                self.songNamesArray.append(object["SongName"] as! String)
                self.songFileArray.append(object["SongFile"] as! PFFile)

            }
        }

        print(self.songFileArray[0])
        print(self.songNamesArray[0])
        print(self.iDArray)


        if let url = NSURL(string: self.songFileArray[0].url!){


        self.playerItem = AVPlayerItem(URL: url)

        self.player = AVPlayer(playerItem: self.playerItem!)   
        }
    }

}

Answer 3

感谢@Aaron提供以下解决方案

func grabSong(){
    let SongQuery = PFQuery(className: "songs")
    SongQuery.getObjectInBackgroundWithId(iDArray[SelectedSongNumber], block:{

        (object: PFObject?, error:NSError?)-> Void in

        if let songFile: PFFile = object?.valueForKey("songFile") as? PFFile {
            AudioPlayer = AVPlayer(URL: songFile.url)
            AudioPlayer.play()
        }
    })
}

Answer 4

在Swift 3中， url 参数是小写的，这解决了我的问题。

player = AVPlayer(url: URL(string: AudioFileURLTemp!))

播放音频解析 - 模糊使用'url'Xcode 7.1 - swift2.0

4 个答案: