Question

将符号（如/ * - +）从string转换为int或double 或者当我将它们从字符串数组转换为双数组时忽略它们的方法。我一直收到错误（＆＃34;附加信息：输入字符串的格式不正确。＆＃34;）

Values.snum = textBox.Text;
var pattern = @"\s*([+*/-])\s*";

textBox.Text = Regex.Replace(textBox.Text, pattern, " $1 ");

int SOption = 0;

string[] parts = Values.snum.Split(' ');
int asize = parts.Length;

double[] num = new double[asize];
for (int c = 0; c < asize; c++)
{
   if ((parts[c] != "*") || (parts[c] != "/") || (parts[c] != "%" ) || (parts[c] != "+" ) || (parts[c] != "-"))
   {
      num[c] = Convert.ToDouble(parts[c]);
   }
}

Answer 1

不确定我的问题是否正确，如果你想尝试获取字符串中的每个数字，请尝试以下方法：

//string input = "2*5+7/5-424)";
Regex getNumbers = new Regex(@"\b(\d)+\b");

var matchColl = getNumbers.Matches(input);

double[] num = new double[matchColl.Count];
int c = 0;

foreach (Match number in matchColl)
    num[c++] = Convert.ToDouble(number.Value);

C ##将符号如/ * - +从string转换为int或double

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