Question

我有一个支持用户帐户的Spring 4 Web应用程序。它有一个用于创建帐户和登录的Web前端。现在我尝试使用REST Web服务创建新用户。我能够get和delete用户使用网络服务，但当我尝试创建新用户或更新现有用户时，我收到http 400错误 - 错误请求。以下是我的代码。

创建用户的服务方法：

@RequestMapping(value="/createuser", method=RequestMethod.POST, headers="Accept=application/json", produces="application/html")
public ResponseEntity<String> createUser(@RequestBody User user){
    logger.debug("insdie put");
    logger.debug(user);
    boolean result = userService.createUserServices(user);
    if(result){
        return new ResponseEntity<>(HttpStatus.CREATED);
    } 
    return new ResponseEntity<>(HttpStatus.BAD_REQUEST);
}

网址＆amp;数据：

http://localhost:8080/XXX/createuser

{
  username: "arun.talwar1@yahoo.com",
  enabled: 1
  password: "arun"
  authority: {
    username: "arun.talwar1@yahoo.com"
    authorityType: "candidate"
  },
  userDetails: {
    username: "arun.talwar1@yahoo.com"
    firstName: "Arun1"
    lastName: "Talwar"
  }
}

请求＆amp;响应：

POST /DummyJobPortal/services/createuser HTTP/1.1
Host: localhost:8080
Connection: keep-alive
Content-Length: 233
User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_5)    AppleWebKit/537.36 (KHTML, like Gecko) Chrome/46.0.2490.80 Safari/537.36
Origin: chrome-extension://hgmloofddffdnphfgcellkdfbfbjeloo
Content-Type: application/json 
Accept: */*
Accept-Encoding: gzip, deflate
Accept-Language: en-US,en;q=0.8

HTTP/1.1 400 Bad Request
Server: Apache-Coyote/1.1
Cache-Control: no-cache, no-store, max-age=0, must-revalidate
Pragma: no-cache
Expires: 0
X-XSS-Protection: 1; mode=block
X-Frame-Options: DENY
X-Content-Type-Options: nosniff
Content-Type: text/html;charset=utf-8
Content-Language: en
Content-Length: 1011
Date: Mon, 09 Nov 2015 17:26:12 GMT
Connection: close

用户类：

@Entity
@Table(name = "users")
@XmlRootElement
public class User {

@Id
@Column(name = "username")
private String username;

@Column(name = "enabled")
private int enabled;

@Column(name = "password")
private String password;

@OneToOne(cascade = { CascadeType.ALL })
@JoinColumn(name = "username")
private Authority authority;

@OneToOne(cascade = { CascadeType.ALL })
@JoinColumn(name = "username")
private UserDetails userDetails;

@XmlElement(name="userDetails")
public UserDetails getUserDetails() {
    return userDetails;
}

public void setUserDetails(UserDetails userDetails) {
    this.userDetails = userDetails;
}

@XmlElement(name="authority")
public Authority getAuthority() {
    return authority;
}

public void setAuthority(Authority authority) {
    this.authority = authority;
}

@XmlElement(name="username")
public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

@XmlElement(name="password")
public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}

@XmlElement(name="enabled")
public int getEnabled() {
    return enabled;
}

public void setEnabled(int enabled) {
    this.enabled = enabled;
}

}

我已经通过互联网寻找答案，但它指出格式错误的请求，服务器无法理解请求。但这与我使用http get方法请求用户时获得的格式相同。任何建议，最受欢迎。

Answer 1

您的JSON格式不正确会阻止服务器处理您的请求。您的属性需要以逗号分隔，并且需要引用属性名称。

以下是JSON

的格式正确的版本

{
    "username": "arun.talwar1@yahoo.com",
    "enabled": 1,
    "password": "arun",
    "authority": {
        "username": "arun.talwar1@yahoo.com",
        "authorityType": "candidate"
    },
    "userDetails": {
        "username": "arun.talwar1@yahoo.com",
        "firstName": "Arun1",
        "lastName": "Talwar"
    }
}

大概400-BadRequest响应是由于服务器无法解析您的JSON请求。

在RESTful Web服务中更新资源时出现Http 400错误请求错误

1 个答案: