Question

我有这个问题：

qry=INSERT INTO assessments (Speaking_and_listening, Reading, Writing, Number, Measure, Geometry, Statistics, Science, ICT, Health_and_well_being, Relationships, Living_in_the_wider_world ) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)

我停止了两个变量和一个循环来进行绑定：

foreach ($subjectListArray as $key=>$subject){
$sss .='s'; 
if (!isset($_POST[str_replace(" ","_",$subject)])){
    $fieldNameValues.='fred';   
}else{
    $fieldNameValues.=$_POST[str_replace(" ","_",$subject)];
}
if ($key!=(count($subjectListArray)-1)){
    $sss.=' ,';
    $fieldNameValues.=', ';
}
}

当我打印出两个数组$sss和$fieldNameValues时，我得到了这个：

s ,s ,s ,s ,s ,s ,s ,s ,s ,s ,s ,s
p2iic, fred, fred, fred, fred, fred, fred, fred, fred, fred, fred, fred

哪个看起来对我来说。

然而，当准备和绑定时：

$record= $conn->prepare($qry);  
$record-> bind_param($sss, $fieldNameValues);

我收到错误告诉我

Warning: mysqli_stmt::bind_param(): Number of elements in type definition string doesn't match number of bind variables

据我所知 - $ ary中有12个，$ sss中有12个，$ fieldNamesValues中有12个

请问有什么不对？

mysqli bind_param类型中元素的数量并不匹配绑定变量

0 个答案: