$uid is 6
public function getUserGroups($uid) {
$sql = "SELECT groups.id, groups.name, groups.type , groups.img_path, DATE_FORMAT(user_group.joined_at,'%e/%c/%Y %H:%i') joined_at FROM groups JOIN user_group ON groups.id = user_group.group_id WHERE groups.id IN (SELECT group_id FROM user_group WHERE user_id = ?)";
$query = $this->db->prepare($sql);
$query->execute(array($uid));
if($query->rowCount()) {
$user_groups = $query->fetchAll();
return $user_groups;
}
return false;
}
此函数可以多次从表中获取真实数据。 输出结果如下:
array (size=2)
0 =>
array (size=10)
'id' => string '4' (length=1)
0 => string '4' (length=1)
'name' => string 'Test Grubu' (length=10)
1 => string 'Test Grubu' (length=10)
'type' => string 'Açık Grup' (length=11)
2 => string 'Açık Grup' (length=11)
'img_path' => string 'images/groupimages/11-09-2015-12-48-56_ic_participation_off.png' (length=63)
3 => string 'images/groupimages/11-09-2015-12-48-56_ic_participation_off.png' (length=63)
'joined_at' => string '9/11/2015 00:48' (length=15)
4 => string '9/11/2015 00:48' (length=15)
1 =>
array (size=10)
'id' => string '4' (length=1)
0 => string '4' (length=1)
'name' => string 'Test Grubu' (length=10)
1 => string 'Test Grubu' (length=10)
'type' => string 'Açık Grup' (length=11)
2 => string 'Açık Grup' (length=11)
'img_path' => string 'images/groupimages/11-09-2015-12-48-56_ic_participation_off.png' (length=63)
3 => string 'images/groupimages/11-09-2015-12-48-56_ic_participation_off.png' (length=63)
'joined_at' => string '9/11/2015 11:50' (length=15)
4 => string '9/11/2015 11:50' (length=15)
user_group:
小组:
我希望得到用户'所有小组。我保存到user_group,并且所有组都保持在组中。
答案 0 :(得分:2)
如果我真的理解你的问题,我想是这样的:
<% form_tag contact_path, remote: true %>
<%= text_field_tag "name %>
<%= email_field_tag "email" %>
<%= submit_tag %>
<% end %>