Question

所以我很难在Stack上找到一个好的答案。我希望运行一个将两个表的信息组合在一起的查询。到目前为止，这就是我所拥有的。实际情况如下：

我将尝试从我这方面解释一下以实现这一目标：

我有两张桌子：

Comparitive_st_sup
___________________

id  | tender_id | item_name | slno | supplier_name | prod_description
________________________________________________________________________

1       401        Collinear   1      OnlineMetals    Description comes here    
2       401        Filter      2      OnlineMetals    Description comes here
3       401        Antenna     3      OnlineMetals    Description Comes here
4       455        Primer      1      KR Electronics  Description comes here
5       455        Chock       2      KR Electronics  Description comes here


comparitive_st_tech_compliance
_______________________________

id | tender_id | item_name  | slno | supplier_name  | tech_analyst_comment
__________________________________________________________________________

1      401        Collinear    1      OnlineMetals     90%
2      401        Filter       2      OnlineMetals     25%
3      401        Antenna      3      OnlineMetals     87%
4      455        Primer       1      KR Electronics   64%
5      455        Chick        2      KR Electronics   80%

Now i am expecting a result like:

401    Collinear     1    OnlineMetals    Description comes here   90%
401    Filter        2    OnlineMetals    Description comes here   25%
401    Antenna       3    OnlineMetals    Description comes here   87%

根据选择的tender_id，值将作为查询字符串传递，并且必须相应地显示记录。帮助赞赏..

我试过了，但结果不合适：

 Select comparitive_st_sup.*,
  comparitive_st_sup.tender_id As tender_id1,
  comparitive_st_sup.supplier_name As supplier_name1,
  comparitive_st_sup.slno As slno1,
  comparitive_st_sup.prod_description As prod_description1,
  comparitive_st_sup.item_name As item_name1,
  comparitive_st_sup.total As total1,
  comparitive_st_tech_compliance.tech_analyst_comment
  From comparitive_st_tech_compliance
  Right Join comparitive_st_sup On comparitive_st_sup.tender_id =
  comparitive_st_tech_compliance.tender_id
  Where comparitive_st_sup.tender_id = 401

我需要显示comparitive_st_sup中的所有字段以及只有一个字段（tech_analyst_comment）和where条件tender_id。现在记录是重复的。它显示了9条记录，而不是显示3条记录。我有任何错误吗？

Answer 1

从您的评论中，我相信comparitive_st_tech_compliance对于单个tender_id，在comparitive_st_sup表中的行中有多行。如果是这样，那么它将返回多行并不重要你使用哪个Join。

Answer 2

您可能需要这样做：

Select comparitive_st_sup.*,
  comparitive_st_sup.tender_id As tender_id1,
  comparitive_st_sup.supplier_name As supplier_name1,
  comparitive_st_sup.slno As slno1,
  comparitive_st_sup.prod_description As prod_description1,
  comparitive_st_sup.item_name As item_name1,
  comparitive_st_sup.total As total1,
  comparitive_st_tech_compliance.tech_analyst_comment
  From comparitive_st_tech_compliance
  Where comparitive_st_sup.tender_id = 401  AND comparitive_st_tech_compliance.tender_id =  tender_id1

Answer 3

SELECT comparitive_st_sup.*,
  comparitive_st_sup.tender_id As tender_id1,
  comparitive_st_sup.supplier_name As supplier_name1,
  comparitive_st_sup.slno As slno1,
  comparitive_st_sup.prod_description As prod_description1,
  comparitive_st_sup.item_name As item_name1,
  comparitive_st_sup.total As total1,
  comparitive_st_tech_compliance.tech_analyst_comment
  FROM comparitive_st_sup, comparitive_st_tech_compliance
  WHERE comparitive_st_sup.tender_id = 401
  AND comparitive_st_tech_compliance.tender_id = comparitive_st_sup.tender_id
  GROUP BY comparitive_st_sup.tender_id;

Answer 4

如果您不想或不能GROUP BY，您可以尝试子查询。您还可以在子查询中ORDER BY日期/ ID。

SELECT
    cs.*,
    cs.tender_id AS tender_id1,
    cs.supplier_name AS supplier_name1,
    cs.slno AS slno1,
    cs.prod_description AS prod_description1,
    cs.item_name AS item_name1,
    cs.total AS total1,
    (
        SELECT
            ct.tech_analyst_comment
        FROM comparitive_st_tech_compliance AS ct
        WHERE ct.tender_id = cs.tender_id
        LIMIT 1
    ) AS tech_analyst_comment
FROM comparitive_st_sup AS cs
WHERE cs.tender_id = 401

<强> LE IF和ONLY如果slno在两个表中都是相同的标识符（comparitive_st_sup.slno = comparitive_st_tech_compliance.slno），那么您可以使用AND comparitive_st_sup.slno = comparitive_st_tech_compliance.slno的额外连接参数将它们连接起来，这样您的初始查询将如下所示：

Select comparitive_st_sup.*,
  comparitive_st_sup.tender_id As tender_id1,
  comparitive_st_sup.supplier_name As supplier_name1,
  comparitive_st_sup.slno As slno1,
  comparitive_st_sup.prod_description As prod_description1,
  comparitive_st_sup.item_name As item_name1,
  comparitive_st_sup.total As total1,
  comparitive_st_tech_compliance.tech_analyst_comment
From comparitive_st_tech_compliance
Right Join comparitive_st_sup On
    comparitive_st_sup.tender_id = comparitive_st_tech_compliance.tender_id AND
    comparitive_st_sup.slno = comparitive_st_tech_compliance.slno
Where comparitive_st_sup.tender_id = 401

但是如果sl *与表* _st_sup和* _tech_compliance不同，则需要在tender_id旁边的产品和注释之间添加关系

comparitive_st_tech_compliance
+-----------------------------------------------------------------------------------------+
| id | tender_id | product_id | item_name  | slno | supplier_name  | tech_analyst_comment |
+-----------------------------------------------------------------------------------------+
|  1 | 401       |     1      | Collinear  |   1  | OnlineMetals   | description          |
+-----------------------------------------------------------------------------------------+

其中comparitive_st_tech_compliance.product_id是Comparitive_st_sup.id，这也使我建议您更改数据库架构（结构）

旁注：因此，从您的数据库结构来看，有一点需要注意的是它的设计很差。您在两个表格中都有重复的字段，因此如果您需要更新ex。 supplier_name您需要更新所有表。现在假设您愿意进行更改，我建议将您的数据拆分为3个表，而不考虑slno可能是2个表之间的标识符。

comparative_supplier
+---------------------+
| id | supplier_name  |
+---------------------+
| 1  | OnlineMetals   |
| 2  | KR Electronics |
+---------------------+

comparitive_st_sup
+--------------------------------------------------------------------+
| id | tender_id | supplier_id | slno | item_name | prod_description |
+--------------------------------------------------------------------+
| 1  | 401       |      1      |   1  | Collinear | description      |
| 2  | 401       |      1      |   2  | Filter    | description      |
| 3  | 401       |      1      |   3  | Antenna   | description      |
| 4  | 455       |      2      |   1  | Primer    | description      |
| 5  | 455       |      2      |   2  | Chock     | description      |
+--------------------------------------------------------------------+

comparitive_st_tech_compliance
+-----------------------------------------+
| id   | id_supply | tech_analyst_comment |
+-----------------------------------------+
| 15   |     1     |         90%          |
| 56   |     2     |         25%          |
| 123  |     3     |         87%          |
| 412  |     4     |         64%          |
| 684  |     5     |         80%          |
+-----------------------------------------+

使用此表结构，您可以轻松地连接表，而无需重复输入和更改字段，而无需更新所有表。

SELECT
    cs.tender_id, sn.supplier_name, cs.slno, cs.item_name,
    cs.prod_description, ct.tech_analyst_comment
FROM comparitive_st_sup AS cs
LEFT JOIN comparative_supplier AS sn ON sn.id = cs.supplier_id
LEFT JOIN comparitive_st_tech_compliance AS ct ON ct.id_supply = cs.id
WHERE cs.tender_id = 401

或者只是更改您的st_sup表并包含技术评论，因为2个表仅因技术评论和产品说明而不同

如何使用where条件连接两个表并显示记录

4 个答案: