Question

我创建了计算侧文件夹中文件大小总和的函数。我可以提前排除文件扩展名

def sourceStatic(path, exclude):

    # exclude list convert to lower 
    exclude = list(map(lambda x:x.lower(), exclude))
    files_size = 0
    files_count = 0
    for root, dirs, files in os.walk(path):
        for fileName in files:
            fname, fileEx = os.path.splitext(fileName)
            fileEx = (fileEx[1:]).lower()
            if not any(fileEx in item for item in exclude):
                print(fileName)
                filePath = os.path.join(root,fileName)
                fileSize = getsize(filePath)
                files_size += fileSize
                files_count += 1

    # return multiple data as dictionary              
    ret = {}
    ret['files_size'] = size(files_size)
    ret['files_size_byte'] = files_size
    ret['files_count'] = files_count
    print(ret)
    return (ret)

上面的方法返回文件夹中的文件数/大小。 os.walk(path)遍历每个文件和子文件夹

问题是一旦发现文件路径超过260个字符getsize(filepath) 如下所示给出错误

  File "C:\Python34\lib\genericpath.py", line 50, in getsize
    return os.stat(filename).st_size
FileNotFoundError: [WinError 3] The system cannot find the path specified:

那么什么是计算文件大小的最佳方法。还有其他方法/ lib吗？

Answer 1

这是由于Windows平台上WinAPI的限制。任何超过260个字符的文件路径都必须以特殊方式处理。阅读此python win32 filename length workaround

filePath = u"\\\\?\\" + filePath
fileSize = getsize(filePath)
....

python FileNotFoundError：[WinError 3] for getsize（filepath）

1 个答案: