Q值。创建名为Participant的类,其中包含名称,年龄和街道地址的字段。包括为每个字段分配参数值的构造函数和返回包含所有值的String的toString()方法。
还包括一个equals()方法,如果它们在所有三个字段中具有相同的值,则确定两个参与者是相等的。
创建一个包含两个阵列的应用程序,每个阵列至少包含5个参赛者 - 一个参加者参加迷你马拉松比赛,另一个参赛者参加跳水比赛。向用户提示两个事件中的参与者将文件保存为Participant.java和TwoEventParticipants.java。* /
到目前为止,这是我的代码。 如何显示两个活动中参加者的价值?
import javax.swing.JOptionPane;
import java.util.*;
public class TwoEventParticipants {
private static Participant mini[] = new Participant[2];
private static Participant diving[] = new Participant[2];
public static void main(String[] args) {
String name="";;
String add="";
int age=0;
Participant p=new Participant(name, age, add);
Participant p1=new Participant(name, age, add);
setParticipant();
setParticipant1();
displayDetail();
displayDetail1();
//Arrays.sort(p1);
if (p.equals(p1)){
System.out.println(p);
}else{
System.out.println(p1);
}
}
public static void setParticipant(){
for (int x = 0; x < mini.length; x++) {
System.out.println("Enter loan details for customer " + (x + 1) + "...");
//Character loanType=getLoanType();
//String loanType=getLoanType();
String name=getName();
String add=getAdd();
int age=getAge();
System.out.println();
mini[x] = new Participant(name, age, add); //<--- Create the object with the data you collected and put it into your array.
}
}
public static void setParticipant1(){
for (int y = 0; y < diving.length; y++) {
System.out.println("Enter loan details for customer " + (y + 1) + "...");
String name=getName();
String add=getAdd();
int age=getAge();
System.out.println();
diving[y] = new Participant(name, age, add);
}
}
// Participant p=new Participant(name,age,add);
//displayDetails();
// System.out.println( p.toString());
public static void displayDetail() {
// for (int y = 0; y < diving.length; y++) {
System.out.println("Name \tAge \tAddress");
//Participant p=new Participant(name,age,add);
for (int x = 0; x < mini.length; x++) {
System.out.println(mini[x].toString());
// System.out.println(diving[y].toString());
}
}
public static void displayDetail1() {
System.out.println("Name \tAge \tAddress");
for (int y = 0; y < diving.length; y++) {
System.out.println(diving[y].toString());
}
}
public static String getName() {
Scanner sc = new Scanner(System.in);
String name;
System.out.print(" Participant name: ");
return name = sc.next();
}
// System.out.print(" Participant name: ");
// name = sc.next();
public static int getAge() {
int age;
System.out.print(" Enter age ");
Scanner sc=new Scanner(System.in);;
return age= sc.nextInt();
}
public static String getAdd() {
String add;
Scanner sc=new Scanner(System.in);;
System.out.print("Enter Address: ");
return add=sc.next();
}
}
Participant with fields for a name, age, and street address
//
public class Participant {
private String name;
private int age;
private String address;
public Participant(String name, int age, String address) {
this.name = name;
this.age = age;
this.address = address;
}
@Override
public String toString() {
return name + " " + age + " " + address ;
}
// include an equals() method that determines two Participants are equal
public boolean equals(Participant[] name,Participant[] age,Participant[] add) {
if (this.name.equals(name) && this.address.equals(address)&& age == age){
return true;
}
else{
return false;
}
}
}
答案 0 :(得分:-1)
这适合您:
for(Participant p : mini){
if(diving.contain(p)){
System.out.pringtln(p.toString()) ;
}
}