我需要从blob创建缩略图并存储在数据库中,所以我有以下功能
function createSquareImage($imgResource, $square_size = 96) {
// get width and height of original image
$originalWidth = imagesx($imgResource);
$originalHeight = imagesy($imgResource);
if ($originalWidth > $originalHeight) {
$thumbHeight = $square_size;
$thumbWidth = $thumbHeight * ($originalWidth / $originalHeight);
}
if ($originalHeight > $originalWidth) {
$thumbWidth = $square_size;
$thumbHeight = $thumbWidth * ($originalHeight / $originalWidth);
}
if ($originalHeight == $originalWidth) {
$thumbWidth = $square_size;
$thumbHeight = $square_size;
}
$thumbWidth = round($thumbWidth);
$thumbHeight = round($thumbHeight);
$thumbImg = imagecreatetruecolor($thumbWidth, $thumbHeight);
$squareImg = imagecreatetruecolor($square_size, $square_size);
imagecopyresampled($thumbImg, $imgResource, 0, 0, 0, 0, $thumbWidth, $thumbHeight, $originalWidth, $originalHeight);
if ($thumbWidth > $thumbHeight) {
$difference = $thumbWidth - $thumbHeight;
$halfDifference = round($difference / 2);
imagecopyresampled($squareImg, $thumbImg, 0 - $halfDifference + 1, 0, 0, 0, $square_size + $difference, $square_size, $thumbWidth, $thumbHeight);
}
if ($thumbHeight > $thumbWidth) {
$difference = $thumbHeight - $thumbWidth;
$half_difference = round($difference / 2);
imagecopyresampled($squareImg, $thumbImg, 0, 0 - $half_difference + 1, 0, 0, $square_size, $square_size + $difference, $thumbWidth, $thumbHeight);
}
if ($thumbHeight == $thumbWidth) {
imagecopyresampled($squareImg, $thumbImg, 0, 0, 0, 0, $square_size, $square_size, $thumbWidth, $thumbHeight);
}
imagedestroy($imgResource);
imagedestroy($thumbImg);
imagedestroy($squareImg);
return $squareImg;
}
我的电话:
$imgBlob = imagecreatefromstring(base64_decode($image->getContent()));
$thumbResource = $this->createSquareImage($imgBlob, 100);
$thumbContent = stream_get_contents($thumbResource);
// Save the stream ($thumbContent) in database
但我得到了例外
Warning: stream_get_contents(): 38 is not a valid stream resource
我做错了什么?
更新1:
如果我删除了行imagedestroy($squareImg);
,我会收到类似的异常消息:
Warning: stream_get_contents(): supplied resource is not a valid stream resource
答案 0 :(得分:1)
您应该使用imagejpeg()
输出图像数据,然后使用ob_start()
和ob_get_clean()
进行捕获。
function createSquareImage($imgResource, $square_size = 96) {
// other code
ob_start();
imagejpeg($squareImg);
$imageData = ob_get_clean();
imagedestroy($imgResource);
imagedestroy($thumbImg);
imagedestroy($squareImg);
return $imageData;
}
这将返回图片的JPEG数据,您无需使用stream_get_contents
。