Question

我希望在Python 3中为lua长字符串创建一个正则表达式。

它们应采用以下格式：

他们应该从＆＃34; [＆＃34;然后是0或更多＆＃34; =＆＃34;然后＆＃34; [＆＃34;再次。接下来应该是字符串并用：＆＃34;]＆＃34;完成，然后是相同数量的等号和＆＃34;]＆＃34;试。

例如：

[[ hello world ]]

或

[===[ hello world ]===]

或

[====[ trick ]==] still ]===] in the ]========] string ]====]

如果重要的话，我正在使用python3

Answer 1

我很确定这就是你所要求的：

\[(=*?)\[(.*?)\]\1\]

\[            #matches '[' literally
    (         #first capture group
        =*?   #match the smallest number of concurrent '=' signs to make this match valid
    )
\[            #matches '[' literally
    (         #second capture group (this is if you just want the string value)
        .*?   #matches the smallest number of characters to make this match valid
    )
\]            #matches ']' literally
    \1        #match an exact copy of the first capture group (makes sure both sides have the same number of equal signs)
\]            #matches ']' literally

Regex101

字符串的正则表达式

1 个答案: