我做错了什么?
问题是我将如何包含equals()
方法,如果它们在所有三个字段中具有相同的值,则确定两个Participant
是相等的?
包括为每个字段分配参数值的构造函数和返回包含所有值的String的toString()
方法。
import javax.swing.JOptionPane;
import java.util.*;
public class Abc {
private static Ab mini[] = new Ab[2];
private static Ab diving[] = new Ab[2];
public static void main(String[] args) {
String name = "";
String add = "";
int age = 0;
Ab p = new Ab(name, age, add);
Ab p1 = new Ab(name, age, add);
setParticipant();
setParticipant1();
displayDetail();
displayDetail1();
if (p == p1) {
System.out.println("equal");
} else {
System.out.println("not equal");
}
}
public static void setParticipant() {
for (int x = 0; x < mini.length; x++) {
System.out.println("Enter detail about participant1 " + (x + 1) + "...");
String name = getName();
String add = getAdd();
int age = getAge();
System.out.println();
mini[x] = new Ab(name, age, add);
//Create the object with the data you collected and put it into your array.
}
}
public static void setParticipant1() {
for (int y = 0; y < diving.length; y++) {
System.out.println("Enter Participant2 " + (y + 1) + "...");
String name = getName();
String add = getAdd();
int age = getAge();
System.out.println();
//mini[x] = new Ab(name, age, add);
//Create the object with the data you collected and put it into your array.
diving[y] = new Ab(name, age, add);
}
}
public static void displayDetail() {
// for (int y = 0; y < diving.length; y++) {
System.out.println("Name \tAge \tAddress");
for (int x = 0; x < mini.length; x++) {
System.out.println(mini[x].toString());
// System.out.println(diving[y].toString());
}
}
public static void displayDetail1() {
System.out.println("Name \tAge \tAddress");
for (int y = 0; y < diving.length; y++) {
System.out.println(diving[y].toString());
}
}
public static String getName() {
Scanner sc = new Scanner(System.in);
String name;
System.out.print(" Participant name: ");
return name = sc.next();
}
// System.out.print(" Participant name: ");
// name = sc.next();
public static int getAge() {
int age;
System.out.print(" Enter age ");
Scanner sc = new Scanner(System.in);
return age = sc.nextInt();
}
public static String getAdd() {
String add;
Scanner sc = new Scanner(System.in);
System.out.print("Enter Address: ");
return add = sc.next();
}
}
public class Ab {
private String name;
private int age;
private String address;
public Ab(String strName, int intAge, String strAddress) {
name = strName;
age = intAge;
address = strAddress;
}
@Override
public String toString() {
return name + " " + age + " " + address;
}
public boolean equals(Participant value) {
boolean result;
if (name.equals(name) && age == value.age && address.equals(address)) {
result = true;
} else {
result = false;
}
return result;
}
}
答案 0 :(得分:6)
equals
应覆盖Object
的{{1}}方法,这意味着它应接受equals
作为参数。
更改
Object
到
public boolean equals(Participant value)
哦,如果您不使用它,那么覆盖@Override
public boolean equals(Object value)
也无济于事。
更改
equals
到
p==p1
答案 1 :(得分:0)
根据您提供的代码,我在任何地方都看不到参与者课程,这意味着public boolean equals(Participant value)
无法开始使用。我建议你的equals方法看起来更像这样:
public boolean equals(Ab value) {
if (this.name.equals(value.name) && this.age == value.age && this.address.equals(value.address)){
return true;
}
else{
return false;
}
}
我还对您的Abc课程进行了一些修改以供您考虑。在我看来,它看起来比原始代码更清晰,更流畅,但同样也是你的选择:)
import javax.swing.JOptionPane;
import java.util.*;
public class Abc {
private static Ab mini[] = new Ab[2];
private static Ab diving[] = new Ab[2];
public static void main(String[] args) {
String name = "";
String add = "";
int age = 0;
Ab p = new Ab(name, age, add);
Ab p1 = new Ab(name, age, add);
for(int x=0; x<mini.length; x++){
System.out.println("Enter detail about participant " + (x + 1) + "...");
setParticipant(mini[x]);
}
for (int y = 0; y < diving.length; y++) {
System.out.println("Enter detail about participant " + (y + 1) + "...");
setParticipant(diving[y]);
}
displayDetail(mini);
displayDetail(diving);
if (p.equals(p1)) {
System.out.println("equal");
} else {
System.out.println("not equal");
}
}
public static void setParticipant(Ab part) {
Scanner sc = new Scanner(System.in);
System.out.print("Name: ");
String name = sc.next();
System.out.print("Age: ");
int age = sc.nextInt();
System.out.print("Address: ");
String add = sc.next();
System.out.println();
part = new Ab(name, age, add); //<--- Create the object with the data you collected and put it into your array.
sc.close();
}
public static void displayDetail(Ab[] parts) {
System.out.println("Name \tAge \tAddress");
for (int x = 0; x < parts.length; x++) {
System.out.println(parts[x].toString());
}
}
}
答案 2 :(得分:-1)
尝试value.name.equals(name)和value.address.equals(address)因为你现在正在比较同样的东西