按钮不会出现在桌面上

时间:2015-11-08 10:38:26

标签: php html sql

以下代码每行添加一个Accept / Decline按钮。但由于某种原因,拒绝按钮不会出现。我不知道什么是错的。已经卡住了一段时间了。帮助将不胜感激。谢谢!

<?php
                    $con=mysqli_connect("localhost","root","","rabco");
                    // Check connection
                    if (mysqli_connect_errno())
                    {
                    echo "Failed to connect to MySQL: " . mysqli_connect_error();
                    }

                    $result = mysqli_query($con,"SELECT * FROM service_request");


                    echo "<table border='1'>
                    <tr>
                    <th>Service ID</th>
                    <th>Service Type</th>
                    <th>Schuduled Date</th>
                    <th>Scheduled Time</th>
                    <th>Client Reference
                    <th>Client ID</th>
                    <th>Admin ID</th>
                    <th>Special Instructions</th>
                    <th>Status</th>
                    <th>Approve</th>
                    <th>Decline</th>
                    </tr>";

                    while($row = mysqli_fetch_array($result))
                    {
                    echo "<tr>";
                    echo "<td>" . $row['Service_ID'] . "</td>";
                    echo "<td>" . $row['Service_type'] . "</td>";
                    echo "<td>" . $row['Sched_date'] . "</td>";
                    echo "<td>" . $row['Sched_time'] . "</td>";
                    echo "<td>" . $row['Client_reference'] . "</td>";
                    echo "<td>" . $row['Client_IDN'] . "</td>";
                    echo "<td>" . $row['Admin_IDN'] . "</td>";
                    echo "<td>" . $row['Special_instructions'] . "</td>";
                    echo "<td>" . $row['Request_status'] . "</td>";
                    echo "<td><a href='approve.php?Service_ID=".$row['Service_ID'].">Approve</a></td>";
                    echo "<td><a href='decline.php?Service_ID=".$row['Service_ID'].">Decline</a></td>";
                    echo "</tr>";
                    }
                    echo "</table>";

                    mysqli_close($con);
                ?>

2 个答案:

答案 0 :(得分:0)

这里有一个错过的结束语:

echo "<td><a href='approve.php?Service_ID=".$row['Service_ID'].">Approve</a></td>";

更改为:

echo "<td><a href='approve.php?Service_ID=".$row['Service_ID']."'>Approve</a></td>";

答案 1 :(得分:0)

您错过了href属性的结束引号,这会产生格式错误的HTML输出。

您需要更改:

echo "<td><a href='approve.php?Service_ID=".$row['Service_ID'].">Approve</a></td>";
echo "<td><a href='decline.php?Service_ID=".$row['Service_ID'].">Decline</a></td>";

echo "<td><a href='approve.php?Service_ID=".$row['Service_ID']."'>Approve</a></td>";
echo "<td><a href='decline.php?Service_ID=".$row['Service_ID']."'>Decline</a></td>";