Question

我在弄清楚我的代码中发生的事情时遇到了一些麻烦（Go figure ...）我还没有涉及到一些最终的int值，但是在我能解决其他一些问题之后我会想到。

我无法弄清楚为什么在将correctGuess更改为true后，我无法在程序退出之前从我的用户那里收到更多输入，以决定是否继续玩。

这应该花费毫秒来自某人的计算机，并在1-110之间收集一个随机数，但有时我会得到负数，似乎无法弄清楚问题是什么。

< / LI>

任何帮助将不胜感激......

import java.util.Scanner;
import java.util.Random;

public class GuessingGame {
    private static final int MIN_NUMBER = 1;
    private static final int MAX_NUMBER = 110;
    private static final int EXIT_VALUE = -1;
    private static final int MAX_GAMES = 256;


    public static void main(String[] argv) {
        System.out.println("*** You are playing the CSC110 Guessing Game ***");
        Scanner scanner = new Scanner(System.in);

        int totalGames = 0;
        int wonGames = 0;
        int guess = 0;

        boolean playing = true;

        while (playing) {
            boolean correctGuess = false;
            totalGames++;

            Random rg = new Random(System.currentTimeMillis());
            int n = MIN_NUMBER + rg.nextInt() % (MAX_NUMBER - MIN_NUMBER);


            System.out.println("Pick a number between 1 and 110 (-1 to exit): ");

            int numberOfTries = 0;

            while (!correctGuess)
            {
                guess = scanner.nextInt();
                numberOfTries++;
                System.out.print(numberOfTries);

                if (guess == n) {
                    System.out.print("Congrats, it took you " + numberOfTries + " try/tries to get the right number!");
                    System.out.print("Do you want to play again? (Yes/No)");
                    correctGuess = true;
                }
                else if(guess != n && numberOfTries < 5)
                {
                    System.out.println("nope... \n");
                }

                else if(guess > n && numberOfTries >= 5)
                {
                    System.out.print("Try something lower \n");
                }
                else if(guess < n && numberOfTries >= 5)
                {
                    System.out.print("Try something higher \n");
                }
            }
            String playAgain = scanner.nextLine();
            if(playAgain.equals("Yes"))
            {
                playing = true;
            }
            else
            {
                playing = false;
            }

        }
    }
}

Answer 1

1：使用以下测试并且它正常工作：

String playAgain = scanner.next();

您也可以考虑修改if语句，如下所示：

if(playAgain.equalsIgnoreCase("Yes") || playAgain.equalsIgnoreCase("Y"))

2：确保数字正确的最简单方法是使用Math.abs（）。

int n = Math.abs(MIN_NUMBER + rg.nextInt() % (MAX_NUMBER - MIN_NUMBER));

猜测游戏Java的问题

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