Question

我的HTML：

<tr class="footer">
  <td colspan="6">
     <div class="quicklinks">           
        <span class="footer_link">          
            <span class="new"> 
               <a href="www.google.com">
                   <img title="mylink" src="" alt="mylink">My link</a>
            </span>
        </span>
     </div>
  </td>

和CSS：

a:link {
    color: red;
}

a:hover {
    color: green;
}

a:active {
    color: green;
}

a:visited {
    color: red;
}

a .footer_link  {

    color: blue;
}

这里是fiddle。如何通过.css将链接设为蓝色？什么是订单，无论我写入多少属性，如.footer .footer_link它都不会变成蓝色。我也尝试了!important，但没有改变。

提前致谢！

Answer 1

你已经写好了。

您的css代码只需要一个核心：

.footer_link a  {
    color: blue;
}

在.footer_link类之后使用锚标记。

我已更新您的小提琴代码： http://jsfiddle.net/5omhc44L/1/

Answer 2

像这样使用：使用后代选择器在footer_link内定位锚标记。

您试图选择不存在的footer_link内部锚点，因此使用a:link样式规则。

＆＃13;

a:link {
  color: red;
}
a:hover {
  color: green;
}
a:active {
  color: green;
}
a:visited {
  color: red;
}
.footer_link a {
  color: blue;
}

＆＃13;

<tr class="footer">
  <td colspan="6">
    <div class="quicklinks">
      <span class="footer_link">          
            <span class="new"> 
               <a href="www.google.com">
                   <img title="mylink" src="" alt="mylink">My link</a>
            </span>
      </span>
    </div>
  </td>

＆＃13;

Answer 3

由于您有a:link { color: red; }

，因此无法更改为蓝色

只需在CSS中删除它。

a:link {
    color: blue;
}

或改为

def main():
    NumberofHouseholds = 0
    inFile = open('program9.txt', 'r')
    HouseIncome = []
    global HouseIncome
    avgincome = 0

    lineRead = inFile.readline()       # Read first record
    while lineRead != '':              # While there are more records
       words = lineRead.split()        # Split the records into substrings
       acctNum = int(words[0])         # Convert first substring to integer
       annualIncome = float(words[1])  # Convert second substring to float
       members = int(words[2])         # Convert third substring to integer
       global members
       global annualIncome
       print(acctNum, format(annualIncome, '.2f'), members, sep=' ')
       HouseIncome.append(annualIncome)
       povertycalc()
       NumberofHouseholds = NumberofHouseholds + 1
       avgincome = (avgincome+annualIncome)/NumberofHouseholds
       lineRead = inFile.readline()    # Read next record

    # Close the file.
    inFile.close() # Close file
    print(avgincome)
    print(HouseIncome)

def povertycalc():
    indexKeep = []
    global indexKeep
    m = members
    povertyLevel = 15930.00 + 4160.00 * (m-2)
    if annualIncome < povertyLevel:
        indexKeep.append(HouseIncome.index(HouseIncome[-1])) #Finds most recent index of household in HouseIncome and adds it to list indexKeep
    print(indexKeep) #not printing the new value added to indexKeep

# Call the main function.
main()

如何将标签更改为蓝色？

3 个答案: