Question

这是我写的代码，错误是getContentResolver().query(MediaStore.Audio.Media.Album.EXTERNAL_CONTENT_URI, proj, null, null, null)有错误，无法解析相册。这是获取专辑列表的正确方法还是有其他更好的方法？我想为流派，艺术家做同样的事情，所以如果他们有不同的方式，请告诉我们：

public class AlbumsFragment extends Fragment{
public AlbumsFragment() {}
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View view=inflater.inflate(R.layout.fragment_albums, container, false);
    ListView albumView=(ListView)view.findViewById(R.id.albumsView);
    ArrayList<String> albumList = new ArrayList<>();
    String[] proj = {MediaStore.Audio.Media.ALBUM};
    final Cursor albumCursor = getActivity().getContentResolver().query(MediaStore.Audio.Media.Album.EXTERNAL_CONTENT_URI, proj, null, null, null);

    if (albumCursor != null) {
        if (albumCursor.moveToFirst()) {
            do {
                int albumIndex = albumCursor.getColumnIndexOrThrow(MediaStore.Audio.Media.ALBUM);
                albumList.add(albumCursor.getString(albumIndex));
            } while (albumCursor.moveToNext());
        }
    }
    albumCursor.close();
    return view;
            }

}

Answer 1

代码将是

您应该像这样查询相册

String[] projection = new String[] { Albums._ID, Albums.ALBUM, Albums.ARTIST, Albums.ALBUM_ART, Albums.NUMBER_OF_SONGS };
String selection = null;
String[] selectionArgs = null;
String sortOrder = Media.ALBUM + " COLLATE NOCASE ASC";
Cursor cursor = contentResolver.query(Albums.EXTERNAL_CONTENT_URI, projection, selection, selectionArgs, sortOrder);

按字母顺序获取所有歌曲的专辑列表

1 个答案: