Question

如何从RequestQueue queue = Volley.newRequestQueue(LeadNowAddUser.this); StringRequest sr = new StringRequest(Request.Method.POST,"http://mzrokz.somee.com/api/LeadNowAppToCore/AddCustomer", new Response.Listener<String>() { @Override public void onResponse(String response) { Log.e("response",response); } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { } }){ @Override protected Map<String,String> getParams(){ Map<String,String> params = new HashMap<String, String>(); params.put("firstName","ankur"); return params; } }; queue.add(sr);文件中读取和存储Python中的8D数组？我的二进制文件看起来像这样。我希望每个字符串都是一行

<html><body>
  <span style="border: 1px solid black; background-color: #CCCCFF"> My text 
  <img style="width: 1em; height: 1em; vertical-align: top; margin-top:1px" 
  src="http://files.softicons.com/download/social-media-icons/stucco-social-media-icons-by-bradley-siefert/png/64x64/stucco-facebook.png"> My text </span>
</body></html>`enter code here`

当我尝试这个时：

public static boolean checkPalindrome(String checkString)

我收到了这个错误

.dat

Answer 1

假设您的.dat文件与您的问题完全相同，我们首先创建一个模仿此格式的数据字符串。我们将其读入数据字符串，然后将其固化为适合加载到numpy

的格式

from StringIO import StringIO

d = StringIO("""['r 11 1602 24 1622 0\n', 'i 26 1602 36 1631 0\n', 
'v 37 1602 57 1621 0\n', 'e 59 1602 76 1622 0\n', 
'r 77 1602 91 1622 1\n', 'h 106 1602 127 1631 0\n', 
'e 127 1602 144 1622 1\n', 'h 160 1602 181 1631 0\n',
'e 181 1602 198 1622 0\n', 'a 200 1602 218 1622 0\n',
'r 218 1602 232 1622 0\n', 'd 234 1602 254 1631 1\n',
't 268 1602 280 1627 0\n', 'h 280 1602 301 1631 0\n',
'e 302 1602 319 1622 1\n', 'd 335 1602 355 1631 0\n'] """)

data = d.read()  # read contents of .dat file
data = data.strip()  # remove trailing newline
data = data.replace('\n', '')  # remove all newlines
data = data.replace("', '", "','")  # clean up separators
data = data[2:-2]  # remove leading and trailing delimiters
data = data.split("','")  # convert into a clean list
data = '\n'.join(data)  # re-combine into a string to load into numpy

print(data)  # have a look at the new string format

生成的.dat字符串如下所示：

r 11 1602 24 1622 0
i 26 1602 36 1631 0
v 37 1602 57 1621 0
e 59 1602 76 1622 0
r 77 1602 91 1622 1
h 106 1602 127 1631 0
e 127 1602 144 1622 1
h 160 1602 181 1631 0
e 181 1602 198 1622 0
a 200 1602 218 1622 0
r 218 1602 232 1622 0
d 234 1602 254 1631 1
t 268 1602 280 1627 0
h 280 1602 301 1631 0
e 302 1602 319 1622 1
d 335 1602 355 1631 0

愚蠢的脚注：我觉得有趣的是，第一列似乎是一个离合器：＆＃34;河流，他听到了......＆＃34;并且最后一列中的1标志着每个单词的结尾:-)无论如何，我的业务都没有。

更严重的是，如果你可以安排从头开始使用这种格式的.dat文件，那么上面的所有步骤都是不必要的。现在我们已经准备好轻松导入一个numpy数组：

import numpy as np

d = StringIO(data)
# The column names 'a' to 'f' are arbitrary 
# and can be changed to suit
# also the numbers are all arbitrarily imported as floats
data = np.loadtxt(d, dtype={'names': ('a', 'b', 'c', 'd', 'e', 'f'),
                            'formats': ('S1', 'f', 'f', 'f', 'f', 'f')})
print(data)

结果如下：

[('r', 11.0, 1602.0, 24.0, 1622.0, 0.0)
 ('i', 26.0, 1602.0, 36.0, 1631.0, 0.0)
 ('v', 37.0, 1602.0, 57.0, 1621.0, 0.0)
 ('e', 59.0, 1602.0, 76.0, 1622.0, 0.0)
 ('r', 77.0, 1602.0, 91.0, 1622.0, 1.0)
 ('h', 106.0, 1602.0, 127.0, 1631.0, 0.0)
 ('e', 127.0, 1602.0, 144.0, 1622.0, 1.0)
 ('h', 160.0, 1602.0, 181.0, 1631.0, 0.0)
 ('e', 181.0, 1602.0, 198.0, 1622.0, 0.0)
 ('a', 200.0, 1602.0, 218.0, 1622.0, 0.0)
 ('r', 218.0, 1602.0, 232.0, 1622.0, 0.0)
 ('d', 234.0, 1602.0, 254.0, 1631.0, 1.0)
 ('t', 268.0, 1602.0, 280.0, 1627.0, 0.0)
 ('h', 280.0, 1602.0, 301.0, 1631.0, 0.0)
 ('e', 302.0, 1602.0, 319.0, 1622.0, 1.0)
 ('d', 335.0, 1602.0, 355.0, 1631.0, 0.0)]

将.dat和.npy加载到Python中

1 个答案: