Question

例如，我有一张桌子

name | ability

kevin|say
kevin|scream
nike |say

在寻找say和scream时，我想得到回应。参数计数可能会改变。

Answer 1

您可以使用group by和having：

执行此操作

SELECT name
FROM t
WHERE ability in ('say', 'scream')
GROUP BY name
HAVING COUNT(*) = 2;

Answer 2

一种方法是：

SELECT * FROM YourTableName WHERE name='kevin' AND ability IN ('say','scream');

另一种方法：

SELECT * FROM YourTableName WHERE name='kevin' AND (ability='say' || ability='scream');

祝你好运!!

Answer 3

这应该有效：

SELECT name FROM tablename WHERE ability IN ('say', 'scream') GROUP BY name

或者：

SELECT DISTINCT name FROM tablename WHERE ability IN ('say', 'scream')

编辑：哦，你正在寻找具有两个能力的名字......那么你可以这样做：

SELECT DISTINCT name from tablename WHERE name IN (SELECT name FROM tablename WHERE ability = 'say') AND name IN (SELECT name FROM tablename WHERE ability = 'scream')

或者更好的是，您可以在第一个查询中添加HAVING子句：

SELECT name FROM tablename WHERE ability IN ('say', 'scream') GROUP BY name HAVING count(*) = 2

当列必须满足多个值时如何选择行？

3 个答案: