我想弄清楚如何从API调用中获取所有字典键,并将它们插入到平面文件中。
#!/usr/bin/env python
import requests
import json
import time
import urllib3
from base64 import b64encode
requests.packages.urllib3.disable_warnings()
#
# GET /dashboards/{dashboardId}/widgets/{widgetId}/value
test_dashboard = "557750bee4b0033aa111a762"
test_widget = "8bad2fc0-5c9b-44f2-a54b-05c8c6f9552b"
apiserver = "http://serveraddress"
userpass = b64encode(b"myuser:mypass").decode("ascii")
headers = { 'Authorization' : 'Basic %s' % userpass }
def get_apicall(dashboardId, widgetId):
response = requests.get(
apiserver + "/dashboards/" +
dashboardId + "/widgets/" +
widgetId + "/value",
headers=headers,
verify=False)
json_data = json.loads(response.text)
print(json.dumps(json_data["result"]["terms"], indent=2))
get_apicall(test_dashboard, test_widget)
输出如下内容:
[user@host ]$ ./shunhosts.py
{
"71.6.216.39": 2,
"71.6.158.166": 2,
"71.6.216.55": 2,
"71.6.216.56": 2
}
我希望代码在平面文本文件中写入/附加每个字典键到新行:即
71.6.216.39
71.6.158.166
71.6.216.55
71.6.216.56
答案 0 :(得分:3)
如果您有字典
d = {
"71.6.216.39": 2,
"71.6.158.166": 2,
"71.6.216.55": 2,
"71.6.216.56": 2
}
您可以使用keys()获取密钥:
d.keys()
dict_keys(['71.6.216.56', '71.6.216.39', '71.6.158.166', '71.6.216.55'])
将其设为新行分隔的字符串:
s = '\n'.join(d.keys())
print(s)
71.6.216.39
71.6.158.166
71.6.216.55
71.6.216.56
然后将其写入文件:
with open('some_file.txt', 'w') as fw:
fw.write(s)
您现在可以进一步将其简化为:
with open('some_file.txt', 'w') as fw:
fw.write('\n'.join(d.keys()))
答案 1 :(得分:0)
json_data["result"]["terms"].keys()
应该为您提供所有密钥。
您应该阅读有关如何打开和写入文件的文档。它在python中非常直接。假设您使用的是python 2.7,这里是链接:https://docs.python.org/2/tutorial/inputoutput.html#reading-and-writing-files
这将是这样的:
f = open(filename, 'w')
f.write(json_data["result"]["terms"].keys())
f.close()
答案 2 :(得分:0)
根据定义,字典具有任意数量的键。没有“钥匙”。你有keys()方法,它给你一个所有键的python列表,你有theiteitems()方法,它返回键值对,所以
for key, value in mydic.iteritems() :
thefile.write("%s\n" % key)
或者只是你可以这样做
for key in mydic.keys():
thefile.write("%s\n" % key)