Question

我是java的初学者，我们被要求创建一个程序，读取20到99之间的整数，并将数字写为单词。如果数字大于99或小于20，程序将报告超出范围错误。当用户键入-1时程序停止。

到目前为止，我有这段代码，我不确定是否有任何错误：

＆＃13;

import java.util.Scanner;
public class Question1 {

   public static void numberToWord(int num, String val) {
            String ones[] = {" ", "ONE", "TWO", "THREE", " FOUR", " FIVE", " SIX", " SEVEN", " EIGHT", " NINE", " TEN", " ELEVEN", " TWELVE", " THIRTEEN", " FOURTEEN", " FIFTEEN", " SIXTEEN", " SEVENTEEN", " EIGHTEEN", " NINETEEN"
            };
            String tens[] = {" ", " ", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};
            if (num > 19) {
                System.out.print(tens[num / 10] + " " + ones[num % 10]);
            } else {
                System.out.print(ones[num]);
            }
            if (num > 0) {
                System.out.println(val);
            }
   }

   public static void main(String[] args) {
      int number = 0;
      
         Scanner scanner = new Scanner(System.in);
         System.out.print("Please type a number between 20 and 99 OR type -1 to end: ");
         number = scanner.nextInt();
         
         while(number!=-1){
            if(number>=20 && number<=99){
               numberToWord((number % 100), " ");
            }
            else {
               System.out.print("Out of bounds. Try Again");
            }
               System.out.print("\nPlease type a number between 20 and 99 OR type -1 to end: ");
               number = scanner.nextInt();
         }
   }
}

＆＃13;

Answer 1

您的代码有效，“FOURTY”一词中只有一个小错字（应该是“FORTY”）。我还会从数组ones和tens中的字符串中删除不必要的空格。你在这里插入一个空格：

System.out.print(tens[num / 10] + " " + ones[num % 10]);

所以数组中的空格字符是多余的。

String ones[] = {
    "", "ONE", "TWO", "THREE", " FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE", "TEN",
    "ELEVEN", "TWELVE", " THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"
};
String tens[] = {
    " ", " ", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"
};

编辑：如果我正在完成这项任务，我可能会编写这样的程序：

import java.util.Scanner;

public class Question1 {

    private static String ones[] = {
            "", "ONE", "TWO", "THREE", " FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE", "TEN",
            "ELEVEN", "TWELVE", " THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"
    };

    private static String tens[] = {
            " ", " ", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"
    };

    public static void numberToWord(int num, String val) {
        if (num > 19)
            System.out.print(tens[num / 10] + " " + ones[num % 10]);
        else
            System.out.print(ones[num]);

        if (num > 0)
            System.out.println(val);
    }

    public static void main(String[] args) {
        int number;
        Scanner scanner = new Scanner(System.in);

        while (true) {
            System.out.print("\nPlease type a number between 20 and 99 OR type -1 to end: ");
            number = scanner.nextInt();

            if (number == -1)
                break; // Leave the loop

            if (number >= 20 && number <= 99)
                numberToWord(number, " ");
            else
                System.out.print("Out of bounds. Try Again");
        }
    }

}

但与您的解决方案相比，只有较小的代码样式改进。

祝学习Java好运！：）

将数字在20-99之间写入java中的单词

1 个答案: