使用用户输入在Python中创建字典

时间:2015-11-06 20:41:02

标签: python

我最近开始学习Python,并且正忙着通过Codecademy教程。我刚刚完成了教程,您可以在其中创建一个程序来确定字典中标记的平均值。下面是当前的代码:

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

class_list = [lloyd, alice, tyler]

def average(numbers):
    total = sum(numbers)
    total = float(total)
    total = total / len(numbers)
    return total
def get_average(student):
    homework = average(student["homework"])
    quizzes = average(student["quizzes"])
    tests = average(student["tests"])
    return homework * 0.1 + quizzes * 0.3 + tests * 0.6
def get_class_average(students):
    results = []
    for student in students:
        results.append(get_average(student))
    return average(results)
print get_class_average(class_list

但我想做的扩展是通过让程序要求用户在第一行输入lloyd以及输入字典中的所有值,使其更加用户友好。此外,我希望每次用户输入字典名称(例如第一行的lloyd)时,程序都会生成一个新字典。然后用class_list填写所有词典。最后我想做到这一点,用户也可以在行中输入标记的权重:

return homework * 0.1 + quizzes * 0.3 + tests * 0.6

我很难做到这一点,所以任何帮助都会受到高度赞赏。

2 个答案:

答案 0 :(得分:2)

您无法生成动态变量名称,但无论如何都不需要。只需使用while输入,然后添加到列表

cancel = False
class_list = []

while (True):
    name = input("Give the name of the user you want to add: ")
    homework = [int(i) for i in input("Homework marks (seperated by spaces): ").split(" ")]
    quizzes = [int(i) for i in input("Quiz marks (seperated by spaces): ").split(" ")]
    tests = [int(i) for i in input("Test marks (seperated by spaces): ").split(" ")]

    class_list.append({
        "name": name,
        "homework": homework,
        "quizzes": quizzes,
        "tests": tests
    })

    cont = input("Want to add another? (Y/N)")
    if cont == "N":
        break;

print(class_list)

[int(i) for i in...]被称为"列表理解。它们遍历字符串编号列表,使它们成为INtegers(使用int())。

答案 1 :(得分:-2)

也许你应该创建一个简单的类?

class Student:
    def __init__(self, name, homework, quizzes, tests):
        self.name = name
        self.homework = homework
        self.quizzes = quizzes
        self.tests = tests

并使用这样的函数输入:

def input_student():
        name = input("Enter name")
        homework = [float(h) for h in input("Enter homework results separated by a space:)]
        # same for quizzes and tests
        class_list.append(Student(name, homework, quizzes, tests))

如果你不想创建一个类,你可以用字典做同样的事情(分配给d [“name”]而不是名字等,其中d是你的字典对象)