// Ch5a程序

Question

// Ch5a程序

＆＃39;我应该使用一种方法来显示用户输入的单词的某个字母。

我需要使用showChar。我无法看到任何明显的错误，而且我已经在这几个小时内完成了工作。＆＃39;

import javax.swing.JOptionPane;
public class Ch5a {
    public static void main(String[] args){
        String inputString = JOptionPane.showInputDialog("What word would you like to analyze?");
        String inputNumberString = JOptionPane.showInputDialog("What letter would you like to see? (Eg: For the second letter of 'dog', input 2)");
        int inputNo;
        inputNo = Integer.parseInt(inputNumberString);
    /**
     At this point, i have an input number from the user(inputNo) and I have a word from the user(inputString).
     I then print the inputNo for testing.
     */
        System.out.println(inputNo);
    //time to call the method.
        char answer;
    //I declare the character answer.
        answer = showChar(inputString, inputNo);
    //i set it equal to the result of the method.
        System.out.println("The " + inputString +" number character in " + inputNo + " is" + answer);

}
    public static char showChar(String inputString, int inputNo){
     //local variable
        char result;
        result = showChar(inputString, inputNo); //user's chosen character
    //returning whatever i want in place of the method call(in this case, "result")
        return result;
    }
}

Answer 1

我想你想要这样的东西：

public static char showChar(String inputString, int inputNo){
    char result;
    result = inputString.charAt(inputNo -1);   // since index starts at 0
    return result;
}

Answer 2

查看String.charAt()方法。我想你想要更像的东西：

    public static char showChar(String inputString, int inputNo){

       char result;

       result = inputString.charAt(inputNo - 1); 

       return result;
    }

或简化：

    public static char showChar(String inputString, int inputNo){
       return inputString.charAt(inputNo - 1); 
    }

请参阅http://www.tutorialspoint.com/java/java_string_charat.htm了解详情

Answer 3

using System;
using System.Text;
using System.Web.UI;
using System.Web.UI.WebControls;

namespace WebApplication1
{
public partial class WebForm1 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        LineBreaker lb = new LineBreaker(4);
        this.Controls.Add(lb);
    }
}

public static class HtmlConstants
{
    public const string Br = @"<br />";
}

public class LineBreaker : WebControl
{
    public LineBreaker(int lineCount)
    {
        LineCount = lineCount;
    }
    public int LineCount { get; set; }

    protected override void Render(HtmlTextWriter writer)
    {
        writer.Write(CreateLineBreaker(LineCount));
        base.Render(writer);
    }

    public string CreateLineBreaker(int howManyLines)
    {
        string result = String.Empty;
        StringBuilder sb = new StringBuilder();
        if (howManyLines > 0)
        {

            for (int i = 0; i < howManyLines; i++)
            {
                sb.Append(HtmlConstants.Br);
            }

            result = sb.ToString();
        }
        return result;
    }
}

我的showChar方法有什么问题？简单的程序介绍方法

// Ch5a程序

3 个答案: