文本IO流编号格式异常

时间:2015-11-06 17:54:45

标签: java ios exception-handling text-files number-formatting

我一直在使用java编写Monopoly,当我从.txt文件中提取租金值时,我遇到了NumberFormatException。

 Exception in thread "main" java.lang.NumberFormatException: For input string: ""

以下是代码:

try{
    //Searching for .txt file
    fileName = "N://java/Monopoly/src/rent.txt";

    //creating FileReader and BuffReader objects
    FileReader input = new FileReader(fileName);

    BufferedReader bufRead = new BufferedReader(input);

    //reading first line
    String line = bufRead.readLine();

    while(line!=""){

        //not sure why, but program doesn't run well without if statement
        if(line!=""){

            //creating array of in variable
            splitArr = line.split(",");

            //creating rent object
            rent r = new rent(Integer.parseInt(splitArr[0]),Integer.parseInt(splitArr[1]),Integer.parseInt(splitArr[2]),Integer.parseInt(splitArr[3]),Integer.parseInt(splitArr[4]),Integer.parseInt(splitArr[5]));

            //storing rent object to a public static Arraylist holding all rents for the game
            rents.add(r);

            //debugging code that has been commented out
            //System.out.println(r.toString());
        }

        //debugging code that has been commented out
        /*for(String s : splitArr){
            System.out.print(s+", ");
        }*/

        //reading next line
        line = bufRead.readLine();

    }
    //closing IO stream
    bufRead.close();

//preventing out of bounds exception error   
}catch (ArrayIndexOutOfBoundsException e){

    System.out.println("Usage: java ReadFile filename: rent\n");  

//preventing IOException error
}catch (IOException e){
    e.printStackTrace();

//I can't quite remember I have this in there. I know it didn't work right without it at some point
}catch(NullPointerException e){

}

当我在第16行取消注释增强的for循环时,我得到一些值,然后是错误,然后是所有其余值,就好像没有问题一样。我注意到当我删除并重新输入错误开始的值时,错误会移动到其他位置。我已经检查了租借类中的参数(它需要6个int),并检查了所有值都很好的.txt文件。 我该如何解决这个问题,或者我不应该担心它并添加另一个catch语句来忽略错误?

1 个答案:

答案 0 :(得分:0)

您正在将字符串与!=进行比较。你应该使用!line.equals("")。 - 救主自我