有没有更好的方法在Symfony 2中构建复杂的查询? 我的真实查询非常复杂,但可以简化为“A和((B和C)或(B和D))”(我知道数学方程为“A和B和(C或D)”,但是我的真实查询无法简化)。 我有使用andWhere和orX的经验,但我的问题是如何在'orX'中使用'和'/'expr() - >和X'。
下面的示例(问题是关于x中的伪代码部分):
$qBuilder = $repo->createQueryBuilder('s')
->select('s.id')
->Where('s.FirstName = :fname')
->Where('s.LastName = :lname')
->andWhere($qBuilder->expr()->orX(
(':email is not empty AND s.Email = :email'),
(':phone is not empty AND s.HomePhone = :phone ),
(':phone is not empty AND s.StudentMobile = :phone ),
(':mphone is not empty AND s.HomePhone = :mphone),
(':mphone is not empty AND s.StudentMobile = :mphone)
))
->setParameter('fname', strtolower($fname))
->setParameter('lname', strtolower($lname))
->setParameter('email', $email)
->setParameter('phone', $phoneNumber)
->setParameter('mphone', $studentmobile);
答案 0 :(得分:2)
只需在里面制作一个andX()
expr。所有表达式函数都是可嵌套的
->andWhere($qb->expr()->orX(
$qb->expr()->andX(':email is not empty', 's.Email = :email'),
$qb->expr()->andX(':phone is not empty', 's.HomePhone = :phone'),
$qb->expr()->andX(':phone is not empty', 's.StudentMobile = :phone'),
$qb->expr()->andX(':mphone is not empty', 's.HomePhone = :mphone'),
$qb->expr()->andX(':mphone is not empty', 's.StudentMobile = :mphone')
))