我正在开发一个HTML / PHP商店网站,为了让人们检查他们想要购买的商品,我在每个产品中都放了一个复选框,名称为" Order_(产品)&#34 ;.问题是,当我需要检查是否选中了该复选框时,它永远不会。我不确定我做错了什么。以下是生成复选框的代码:
while ($i < $num_linhas) {
$row = pg_fetch_row($result, $i);
echo "<div class='product'>
<h3>".$row[2]."</h3>
<img src='common/images/".$tipo_produto."/".$row[1].".jpg' alt='".$row[1]."'>
<br>";
if($_SESSION['tipo'] == "cliente")
{
echo '<form method="POST"><input type="checkbox" name="encomendar_'.$row[0].'"></form>Encomendar';
}
$i++;
echo "</div>";
}
以及检查它们是否被检查的代码(不同的脚本):
while($i < $num_linhas)
{
$row = pg_fetch_row($result_1, $i);
if(isset($_POST['encomendar_'.$row[0].'']))
{
echo $row[0];
$query = "SELECT * from biofood.encomenda";
$result_2 = pg_exec($conn, $query);
$num_linhas = pg_num_rows($result_2);
$j = $num_linhas + 1;
$t = time();
$data = date('y-m-d');
$hour = date('H:i');
$id_cliente = $_SESSION['id'];
$query = "Insert into biofood.encomenda(id,data,hora,id_cliente,id_produto,estado) VALUES('".$j."','".$data."','".$hour."','".$id_cliente."','".$row[0]."','Não tratada')";
$result_3 = pg_exec($conn, $query);
}
$i++;
}
答案 0 :(得分:0)
您在需要时不会使用值
echo '<form method="POST"><input type="checkbox"
name="encomendar_'.$row[0].'" checked ></form>Encomendar';
}
答案 1 :(得分:0)
您必须为输入添加值
echo '<form method="POST"><input type="checkbox" name="encomendar_'.$row[0].'" value="$row[0]"></form>Encomendar';
例如。
之后,您将能够检查它是否已设置:
while($i < $num_linhas)
{
$row = pg_fetch_row($result_1, $i);
if(isset($_POST['encomendar_'.$row[0]]))
{
echo $row[0];
$query = "SELECT * from biofood.encomenda";
$result_2 = pg_exec($conn, $query);
$num_linhas = pg_num_rows($result_2);
$j = $num_linhas + 1;
$t = time();
$data = date('y-m-d');
$hour = date('H:i');
$id_cliente = $_SESSION['id'];
$query = "Insert into biofood.encomenda(id,data,hora,id_cliente,id_produto,estado) VALUES('".$j."','".$data."','".$hour."','".$id_cliente."','".$row[0]."','Não tratada')";
$result_3 = pg_exec($conn, $query);
}
$i++;
}