Question

我尝试在完成foreach循环后得到所有数据但不知何故总是得到[]

 $scope.temp = [];
    angular.forEach(seasonStageIds, function (seasonStageId, index) {

        playerService.getPlayerProfile(seasonStageId, $stateParams.params.playerSename).then(function (data) {

            playerService.getPlayerPositionPerSeason(seasonStageId, data.data.Id).then(function (data) {
                console.log(data);
                _.chain(data)
                 .groupBy('Position')
                 .map(function (value, key) {

                     var goals = _.reduce(value, function (memo, num) {
                         return memo + num.Goals;
                     }, 0);
                     var apps = _.reduce(value, function (memo, num) {

                         return memo + num.Apps;
                     }, 0);
                     var assists = _.reduce(value, function (memo, num) {
                         return memo + num.Assist;
                     }, 0);
                     var ratings = _.reduce(value, function (memo, num) {
                         return memo + num.Rating;
                     }, 0);

                     var position = {
                         Position: key,
                         Apps: apps,
                         Assists: assists,
                         Ratings: ratings,
                         Goals: goals                        
                     };       
                     console.log(position);          >> correct data
                     $scope.temp.push(position);
                 });
            });


        });
    });


    $q.all($scope.temp).then(function (data) {
        console.log( data);   >> show []
    })

我做错了什么？谢谢大家。

Answer 1

$q.all仅适用于承诺！即等待所有的所有承诺完成，然后运行'then'函数。您正在传递一个数组作为参数。要获得所需内容，请尝试以下操作：

$scope.temp = [];
angular.forEach(seasonStageIds, function (seasonStageId, index) {

    var promise =  playerService.getPlayerProfile(seasonStageId, $stateParams.params.playerSename).then(function (data) {

        return playerService.getPlayerPositionPerSeason(seasonStageId, data.data.Id).then(function (data) {
            return _.chain(data)
             .groupBy('Position')
             .map(function (value, key) {

                 var goals = _.reduce(value, function (memo, num) {
                     return memo + num.Goals;
                 }, 0);
                 var apps = _.reduce(value, function (memo, num) {

                     return memo + num.Apps;
                 }, 0);
                 var assists = _.reduce(value, function (memo, num) {
                     return memo + num.Assist;
                 }, 0);
                 var ratings = _.reduce(value, function (memo, num) {
                     return memo + num.Rating;
                 }, 0);

                 var position = {
                     Position: key,
                     Apps: apps,
                     Assists: assists,
                     Ratings: ratings,
                     Goals: goals                        
                 };       

                 return position;
             });
        });
    });

    $scope.temp.push(promise);
});


$q.all($scope.temp).then(function (data) {
    console.log( data);
});

E.g。 http://jsfiddle.net/HB7LU/19677/

AngularJS等待foreach内部的所有异步调用？

1 个答案: