Question

我在下面有这个查询：

SELECT * 
FROM mydb.users
left join mydb.jobs
on users.user_id = jobs.job_id;

我曾经在orm查询中转换它们，如下所示：

  return 
  $qb = $this->entityManager->createQueryBuilder();
  $qb->select('rb', 'l')
     ->from('Admin\Entity\Users', 'rb')
     ->leftJoin(
        'Admin\Entity\Jobs',
        'l',
        \Doctrine\ORM\Query\Expr\Join::WITH,
        'rb.user_id = l.job_id'
       )
     ->getQuery()
     ->getResult(AbstractQuery::HYDRATE_ARRAY);

但它仍然有效。我收到以下错误：

PHP Fatal error: Call to a member function createQueryBuilder() on null

请帮助我不知道该怎么做。

Answer 1

试试这个

myView.setLayerType(View.LAYER_TYPE_SOFTWARE, null);

或确保已分配$ this-＆gt; entityManager。

Answer 2

这只是意味着您在public static String excutePost(String targetURL, String urlParameters) { URL url; HttpURLConnection connection = null; try { //Create connection url = new URL(targetURL); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); connection.setRequestProperty("Content-Length", "" + Integer.toString(urlParameters.getBytes().length)); connection.setRequestProperty("Content-Language", "en-US"); connection.setUseCaches (false); connection.setDoInput(true); connection.setDoOutput(true); //Send request DataOutputStream wr = new DataOutputStream ( connection.getOutputStream ()); wr.writeBytes (urlParameters); wr.flush (); wr.close (); //Get Response InputStream is = connection.getInputStream(); BufferedReader rd = new BufferedReader(new InputStreamReader(is)); String line; StringBuffer response = new StringBuffer(); while((line = rd.readLine()) != null) { response.append(line); response.append('\r'); } rd.close(); return response.toString(); } catch (Exception e) { String g=e.toString(); Log.d("errererer", g); return null; } finally { if(connection != null) { connection.disconnect(); } } }中没有EntityManager个实例。

我的猜测是$this->entityManager可能为null，因为你没有在类实例中注入$this->entityManager。

左边加入了doctrine orm Zend框架

2 个答案: