Question

我已经使用Jetty作为服务器编写了一个应用程序。我希望将我的应用程序打包成.jar，以便稍后将其放入Docker容器中。

当我通过IntelliJ运行我的应用程序时，一切似乎都正常工作，我可以从index.html到达localhost:2222。但是，当我打包我的应用程序（使用mvn clean compile assembly:single）并通过在shell中键入java -jar myapplication.jar来运行我的jar时，index.html上的localhost:2222会返回HTTP Error 404。< / p>

我的App.java：

public class App  {
    public static void main( String[] args ) throws Exception {
        ResourceConfig config = new ResourceConfig();
        config.packages("mypackage");
        ServletHolder servlet = new ServletHolder(new ServletContainer(config));

        Server server = new Server(2222);


        ResourceHandler handler = new ResourceHandler();
        handler.setBaseResource(org.eclipse.jetty.util.resource.Resource
                .newClassPathResource("index.html"));

        ServletContextHandler context = new ServletContextHandler(server, "/*");
        context.addServlet(servlet, "/*");


        HandlerList handlers = new HandlerList();
        handlers.addHandler(handler);
        handlers.addHandler(context);

        server.setHandler(handlers);

        try {
            server.start();
            server.join();
        } finally {
            server.destroy();
        }
    }
}

当在IntelliJ 和中运行应用程序作为jar时，我得到以下输出（可能感兴趣？）：

2015-11-06 09:25:00.991:INFO::main: Logging initialized @279ms
2015-11-06 09:25:01.238:WARN:oejsh.ContextHandler:main: o.e.j.s.ServletContextHandler@490d6c15{/,null,null} contextPath ends with /*
2015-11-06 09:25:01.238:WARN:oejsh.ContextHandler:main: Empty contextPath
2015-11-06 09:25:01.250:INFO:oejs.Server:main: jetty-9.2.3.v20140905
Nov 06, 2015 9:25:01 AM org.glassfish.jersey.server.ApplicationHandler initialize
INFO: Initiating Jersey application, version Jersey: 2.7 2014-03-12 18:11:31...
2015-11-06 09:25:02.294:INFO:oejsh.ContextHandler:main: Started o.e.j.s.ServletContextHandler@490d6c15{/,null,AVAILABLE}
2015-11-06 09:25:02.306:INFO:oejs.ServerConnector:main: Started ServerConnector@268f106e{HTTP/1.1}{0.0.0.0:2222}
2015-11-06 09:25:02.306:INFO:oejs.Server:main: Started @1688ms

我没有发布我的Jersey方法文件，因为我认为它与我的问题无关。

那么，将这个打包到能够识别我index.html localhost:2222的jar的魔力是什么？是IntelliJ中的一些环境设置吗？

干杯

Answer 1

首先，不要混用ResourceHandler和ServletContextHandler，你正在重复静态内容的努力（ 3次与泽西一起玩） 并且会得到不可靠的结果。

删除ResourceHandler，设置所需的ServletContextHandler.setBaseResource()，然后在您的上下文中添加DefaultServlet。

    // Figure out what path to serve content from
    ClassLoader cl = App.class.getClassLoader();
    // We look for a file, as ClassLoader.getResource() is not
    // designed to look for directories (we resolve the directory later)
    URL f = cl.getResource("static-root/index.html");
    if (f == null)
    {
        throw new RuntimeException("Unable to find resource directory");
    }

    // Resolve file to directory
    URI webRootUri = f.toURI().resolve("./").normalize();
    System.err.println("Main Base Resource is " + webRootUri);

    // Setup the basic application "context" for this application at "/"
    // This is also known as the handler tree (in jetty speak)
    ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
    context.setContextPath("/");
    context.setBaseResource(Resource.newResource(webRootUri));
    server.setHandler(context);

    // Jersey setup
    ResourceConfig config = new ResourceConfig();
    config.packages("mypackage");
    context.addServlet(new ServletHolder(new ServletContainer(config)), "/*");

    // Lastly, the default servlet for root content (always needed, to satisfy servlet spec)
    // It is important that this is last.
    ServletHolder holderDef = new ServletHolder("default",DefaultServlet.class);
    holderDef.setInitParameter("dirAllowed","true");
    context.addServlet(holderDef,"/");

注意：由于你在url-pattern /*设置Jersey，你应该知道Jersey负责提供所有静态内容，而不是Jetty。

在IntelliJ中运行应用程序与jar

1 个答案: