我做了一些CSS样式更改后,我的表现在与右侧对齐。
我尝试添加表align="center"
,但它也无效。
请让我知道我错过了什么。
table {
//font: 11px/24px Verdana, Arial, Helvetica, sans-serif;
border-collapse: collapse;
width: 320px;
}
th {
padding: 0 0.5em;
text-align: left;
}
td {
border-bottom: 1px solid #CCC;
padding: 0 0.5em;
}
td.width {
width: 190px;
}
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Browse CD</title>
<link rel="stylesheet" type="text/css" href="CDcss.css" />
</head>
<body>
<div id="wrapper">
<div id="banner">
</div>
<nav id="navigation">
<ul id="nav">
<li><a href="index.php">Home</a></li>
<li><a href="DisplayCD.php">Browse</a></li>
<li><a href="SearchCD.php">Search</a></li>
<li><a href="Credit.php">Credit</a></li>
</ul>
</nav>
<style>
td, th {
border: 1px solid black;
}
th {
background-color: grey;
color: white;
}
</style>
<?php
header('Content-type: text/html; charset=iso-8859-1');
include 'database_conn.php';
$sql = "SELECT nmc_cd.CDID, nmc_cd.CDTitle, nmc_cd.CDYear, nmc_cd.CDPrice, nmc_category.catDesc, nmc_cd.catID
FROM nmc_cd
LEFT JOIN nmc_category ON nmc_cd.catID=nmc_category.catID";
$queryresult = mysqli_query($conn, $sql)
or die (mysqli_error($conn));
echo '<table class=table>';
echo '<tr><th>Music Title</th><th>Year</th><th>Price</th> <th>Category</th><tr>';
echo '</table';
while($row = mysqli_fetch_assoc($queryresult)) {
$iCDID = $row['CDID'];
$CDTitle = $row['CDTitle'];
$CDYear = $row['CDYear'];
$CDPrice = $row['CDPrice'];
$CDCat = $row['catDesc'];
$CDCatID = $row['catID'];
echo "<table><tr><td>
<a href = \"editCDForm.php?itemCode=$iCDID\">$CDTitle</a>
</td><td> $CDYear
</td><td> $CDPrice
</td><td> $CDCat
</td></tr>
</table";
}
mysqli_free_result($queryresult);
mysqli_close($conn);
?>
</body>
</html>
答案 0 :(得分:0)
提供您网站的链接或此表格所在的页面。