我有以下示例xml文件:
<?xml version="1.0" encoding="utf-8" ?>
<categories>
<category id="1" name="Car">
<category id="12" name="Electrical">
<category id="18" name="On-Road">
<category id="127" name="Carisma"></category>
<category id="128" name="HPI - Maverick"></category>
<category id="452" name="HSP"></category>
<category id="130" name="Other"></category>
</category>
<category id="16" name="Off-Road">
<category id="132" name="HPI - Maverick"></category>
<category id="225" name="Carisma"></category>
<category id="315" name="HSP"></category>
<category id="420" name="Other"></category>
</category>
</category>
</category>
</categories>
我需要的是具有特定值的任何子节点的所有父节点。
例如,如果id值为128, 然后它会回应:汽车/电气/路上/ HPI - Maverick
如果id值为12,则它将回显 Car / Electrical
继续......
我已设法获取具有特定id值的节点(如下),但我无法弄清楚如何从所选节点获取父链。
<?php
$file = "http://www.localhost.com/categories.xml";
$microline = new SimpleXMLElement($file, null, true);
foreach($microline as $cat){
if ($cat->children['id'] = $catid) {
$current_cat_name = $cat->xpath("//*[@id=$catid]/@name")[0];
echo $current_cat_name;
}
}
unset($microline);
?>
答案 0 :(得分:0)
如果您使用XPath //*[@id=$catid]/ancestor-or-self::category/@name
,那么您拥有所有属性值,只需要将它们与PHP中的斜杠字符连接起来。
这样做,例如
$xml = <<<'EOB'
<categories>
<category id="1" name="Car">
<category id="12" name="Electrical">
<category id="18" name="On-Road">
<category id="127" name="Carisma"></category>
<category id="128" name="HPI - Maverick"></category>
<category id="452" name="HSP"></category>
<category id="130" name="Other"></category>
</category>
<category id="16" name="Off-Road">
<category id="132" name="HPI - Maverick"></category>
<category id="225" name="Carisma"></category>
<category id="315" name="HSP"></category>
<category id="420" name="Other"></category>
</category>
</category>
</category>
</categories>
EOB;
$root = new SimpleXMLElement($xml);
$id = 127;
$cats = $root->xpath("//*[@id=$id]/ancestor-or-self::category");
$path = implode('/', array_map(function($a) { return $a['name']; }, $cats));
echo $path;
会输出Car/Electrical/On-Road/Carisma
。