Question

我有以下javascript类

var a = function () {
    this.data = {};
};

a.prototype.parseString = function (string) {
    this.data = string.split(',');
}

a.prototype.performOperationB = function () {
    this.iPo = _.map(this.data, function () {
        if (item.indexOf('ip') > -1) {
            return item;
        }
    });
}

a.prototype.save = function (string) {
    this.parseString(string)
        .performOperationB()
        // some other chained methods
}
var b = new a();

b.save(string);

会返回TypeError: Cannot read property 'performOperationB' of undefined

是否可以在另一个方法中一个接一个地链接原型方法？

Answer 1

从

返回this

a.prototype.parseString = function(string) {
   this.data  = string.split(',');
   return this;
}

因为now方法返回undefined

＆＃13;

var a = function () {
  this.data = {};
};

a.prototype.parseString = function (string) {
  this.data = string.split(',');
  return this;
}

a.prototype.performOperationB = function () {
  this.iPo = _.map(this.data, function (item) {
    if (item.indexOf('ip') > -1) {
      return item;
    }
  });
}

a.prototype.save = function (string) {
  this.parseString(string)
     .performOperationB()
}
var b = new a();

b.save('string');

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore.js"></script>

＆＃13;

方法链接返回undefined

1 个答案: