当type =“latex”时，如何将stargazer表对齐到左边？

Question

我在自动rmarkdown pdf文档中使用stargazer包来制作漂亮的表格。默认情况下，Stargazer将其表格放在页面的中心。我如何让stargazer生成乳胶代码，使表格左对齐？

这是我的意思的一个例子：

library(stargazer)

data_object <- structure(list(test = structure(c(1L, 1L, 2L, 2L), .Label = c("test1",  "test2"), class = "factor"), test2 = structure(1:4, .Label = c("1",        "2", "3", "4"), class = "factor")), .Names = c("test", "test2"), row.names = c(NA, -4L), class = "data.frame")

stargazer(data_object,title="table test",summary=FALSE,rownames=FALSE,type="latex",header=FALSE)

它产生的代码是：

\begin{table}[!htbp] \centering 
  \caption{table test} 
  \label{} 
\begin{tabular}{@{\extracolsep{5pt}} cc} 
\\[-1.8ex]\hline 
\hline \\[-1.8ex] 
test & test2 \\ 
\hline \\[-1.8ex] 
test1 & 1 \\ 
test1 & 2 \\ 
test2 & 3 \\ 
test2 & 4 \\ 
\hline \\[-1.8ex] 
\end{tabular} 
\end{table}

请注意\centering。如何在不改变乳胶代码本身的情况下改变它？

Answer 1

\centering似乎是hard coded into the function。您可以做的是使用\centering删除sub（例如sub(" \\\\centering", "", out)）。

这是我使用的块。我使用capture.output来阻止stargazer输出我认为的中间结果。

<<results = "asis">>=
library(stargazer)

data_object <- structure(list(test = structure(c(1L, 1L, 2L, 2L), .Label = c("test1",  "test2"), class = "factor"), test2 = structure(1:4, .Label = c("1",        "2", "3", "4"), class = "factor")), .Names = c("test", "test2"), row.names = c(NA, -4L), class = "data.frame")

out <- capture.output(stargazer(data_object,title="table test",summary=FALSE,rownames=FALSE,type="latex",header=FALSE))
out <- sub(" \\\\centering", "", out)
cat(out)
@