{
"gender" : "Male",
"city" : "chenna",
"instituteName" : "srm",
"profileImage" : "ProfileImage",
"dob" : "DOB",
"emailAddress" : "saxasx",
"isStudent" : "true",
"studentIdValidity" : "Month2Year5",
"studentIdImage" : "IDImage",
"name" : "xasx",
"phoneNumber" : "9092256227"
}
NSDictionary *dic ;
dic = [[NSUserDefaults standardUserDefaults]objectForKey:@"fizzstudentjson"];
NSLog(@"%@",dic);
NSString *strng = [dic objectForKey:@"city"];
NSLog(@"%@",strng);
当我尝试使用我的应用时,访问nsstring中的dictonary值正在崩溃 我编写的代码帮助了我
答案 0 :(得分:0)
这对我有用。
NSDictionary *dictionary = @{
@"gender" : @"Male",
@"city" : @"chenna",
@"instituteName" : @"srm",
@"profileImage" : @"ProfileImage",
@"dob" : @"DOB",
@"emailAddress" : @"saxasx",
@"isStudent" : @"true",
@"studentIdValidity" : @"Month2Year5",
@"studentIdImage" : @"IDImage",
@"name" : @"xasx",
@"phoneNumber" : @"9092256227"
};
[[NSUserDefaults standardUserDefaults] setObject:dictionary forKey:@"fizzstudentjson"];
NSDictionary *dic = [[NSUserDefaults standardUserDefaults]objectForKey:@"fizzstudentjson"];
NSLog(@"%@",dic);
NSString *strng = [dic valueForKey:@"city"];
NSLog(@"%@",strong);
<强>结果:chenna 强>
答案 1 :(得分:0)
作为记录数据,它可能是NSString格式,而不是NSDictionary。所以你需要在使用前将它转换为NSDictionary。试试这段代码
NSString *fizzstudentjson = [[NSUserDefaults standardUserDefaults]objectForKey:@"fizzstudentjson"];
NSData *data = [fizzstudentjson dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
NSString *city = dictionary[@"city"];