Question

我想使用python在c ++中实现以下逻辑。

struct hash_string ///
{
    hash_string() {}

    uint32_t operator ()(const std::string &text) const
    {
        //std::cout << text << std::endl;
        static const uint32_t primes[16] =
        {
            0x01EE5DB9, 0x491408C3, 0x0465FB69, 0x421F0141,
            0x2E7D036B, 0x2D41C7B9, 0x58C0EF0D, 0x7B15A53B,
            0x7C9D3761, 0x5ABB9B0B, 0x24109367, 0x5A5B741F,
            0x6B9F12E9, 0x71BA7809, 0x081F69CD, 0x4D9B740B,
        };

        //std::cout << text.size() << std::endl;
        uint32_t sum = 0;
        for (size_t i = 0; i != text.size(); i ++) {
            sum += primes[i & 15] * (unsigned char)text[i];
            //std::cout << text[i] <<std::endl;
            // std::cout << (unsigned char)text[i] << std::endl;
        }
        return sum;
    }
};

python版本是这样的，尚未完成，因为我还没有找到将文本转换为unsigned char的方法。所以，请帮忙！

# -*- coding: utf-8 -*-

text = u'连衣裙女韩范'

primes = [0x01EE5DB9, 0x491408C3, 0x0465FB69, 0x421F0141,
                0x2E7D036B, 0x2D41C7B9, 0x58C0EF0D, 0x7B15A53B,
                0x7C9D3761, 0x5ABB9B0B, 0x24109367, 0x5A5B741F,
                0x6B9F12E9, 0x71BA7809, 0x081F69CD, 0x4D9B740B]

//*text[i] does not work (of course), but how to mimic the logic above
rand = [primes[i & 15]***text[i]** for i in range(len(text))]

print rand

sum_agg = sum(rand)

print sum_agg

拿text = u＆＃39;连衣裙女韩范＆＃39;例如，c ++版本为text.size（）返回18，sum为2422173716，而在python中，我不知道如何使它成为18。

文本大小的平等至关重要，至少是一个开始。

Answer 1

因为你使用的是unicode，为了精确再现，你需要在一系列字节中转换text（c ++中的字符）。

bytes_ = text.encode("utf8") 
# when iterated over this will yield ints (in python 3)
# or single character strings in python 2

你应该使用更多的pythonic习语来迭代一对序列

pairs = zip(bytes_, primes)

如果bytes_比素数更长，该怎么办？使用itertools.cycle

from itertools import cycle
pairs = zip(bytes_, cycle(primes))

所有在一起：

from itertools import cycle

text = u'连衣裙女韩范'

primes = [0x01EE5DB9, 0x491408C3, 0x0465FB69, 0x421F0141,
                0x2E7D036B, 0x2D41C7B9, 0x58C0EF0D, 0x7B15A53B,
                0x7C9D3761, 0x5ABB9B0B, 0x24109367, 0x5A5B741F,
                0x6B9F12E9, 0x71BA7809, 0x081F69CD, 0x4D9B740B]

# if python 3
rand = [byte * prime for byte, prime in zip(text.encode("utf8"), cycle(primes))]
# else if python 2 (use ord to convert single character string to int)
rand = [ord(byte) * prime for byte, prime in zip(text.encode("utf8"), cycle(primes))]
hash_ = sum(rand)

使用python在c ++中实现逻辑，怎么样？

1 个答案: