Question

我有这种阵列：

var foo = [ { "a" : "1" }, { "b" : "2" }, { "a" : "1" } ];

我想过滤它：

var bar = [ { "a" : "1" }, { "b" : "2" }];

这是我的plunker

在plunker的第7行，当我写return JSON.stringify( x );时它很好但是返回字符串JSON ..但是当我写return x;时它变坏了并且不返回Unique JSON。

Answer 1

您只需使用var jsonObjdata = []; var yearExist = ""; var weekExist = ""; var SampleRequestBody = {}; $.each(data, function (key, value) { if (value.year != yearExist) { SampleRequestBody.week = value.week; SampleRequestBody.firstYear = value.changes; yearExist = value.year; } else if (value.year == yearExist && value.week == weekExist + 1) { SampleRequestBody.secondYear = value.changes; } else if (value.year == yearExist && value.week == weekExist + 1) { SampleRequestBody.thildYear = value.changes; jsonObjdata.push(SampleRequestBody); } });即可，无需收集：

uniq

此处更新了plunk：http://plnkr.co/edit/KYW6UybdiBxuvOVX8naP?p=preview

Answer 2

first you can download underscorejs then you can use the following code

 var foo = [{ "a": "1" }, { "b": "2" }, { "a": "1" }];
            var result = _.uniq(foo, function (obj) {
                return JSON.stringify(obj);
            });


 refere the following url  http://underscorejs.org/

Answer 3

您可以使用var uniqueList =_.uniq(foo, 'a');以下是doc：https://lodash.com/docs#uniq 这里是plunker：http://plnkr.co/edit/HkirGPrs3dGZMUEnEKiT?p=preview

获取JSON的唯一对象

3 个答案: