Question

#!/bin/bash

BACKUP=backup_date
SOURCE=Arithmetic_Operators

echo "Taking backup from ${SOURCE} directory to backup directory ${BACKUP} .."

# Checking the source directory ${SOURCE} exists or not ! if not exists die
# Script is unsuccessful with exit status # 1

[ ! -d $SOURCE ] && echo "source directory $SOURCE not found"
exit 1

# Checking the backup directory ${BACKUP} exists or not ! if not exists die
# Script is unsuccessful with exit status # 2

[ ! -d $BACKUP ] && echo "backup directory $BACKUP not found"
exit 2

# Let Start the backing up

tar cvf $SOURCE $BACKUP 2> /wrong/logs.txt

if [ $? -ne 0 ]
then
   # die with unsuccessful shell script termination exit status # 3
   echo "An error occurred while making a source directory backup, see /wrong/logs.txt file".
   exit 3 
fi

这是我将源目录（Arithmetic_Operators）备份到目标目录（backup_date）的脚本，在运行脚本时我的脚本以消息

结束

从Arithmetic_Operators目录备份到备份目录backup_date ..
源目录未找到Arithmetic_Operators

我错误地说这个脚本没有运行的原因你能帮我解决这个问题吗？

Answer 1

这些行意味着脚本无条件退出：

[ ! -d $SOURCE ] && echo "source directory $SOURCE not found"
exit 1

你可能意味着：

if [ ! -d $SOURCE ]
then
    echo "source directory $SOURCE not found" >&2
    exit 1
fi

或者也许：

[ ! -d $SOURCE ] && { echo "source directory $SOURCE not found" >&2; exit 1; }

请注意，错误消息应发送到标准错误，而不是标准输出。在消息中包含脚本名称（$0）并不是一个坏主意;它有助于识别生成/检测到问题的脚本。

检查$BACKUP目录后，您遇到了类似的问题。

另外，作为一般规则，用双引号括起变量引用：

[ ! -d "$SOURCE" ] && { echo "source directory $SOURCE not found" >&2; exit 1; }

（当然，第二个引用已在双引号内。）

shell脚本将源目录备份到备份目录

1 个答案: