我想从源文件夹中复制所有.xlsx文件,并通过附加" _Report"重命名。 (vb脚本代码) 我使用以下代码:
objFSO.CopyFile srcpath&"*.xlsx",destpath&"*_Report.xlsx",True
但它不起作用。有人可以帮帮我吗?
答案 0 :(得分:1)
试试这个剧本:
Option Explicit
Dim File,SourceFolder,DestinationFolder,Ws
SourceFolder = Browse4Folder()
DestinationFolder = SourceFolder & "\NewFolder"
Call BuildFullPath(DestinationFolder)
Call Scan4Folder(SourceFolder)
MsgBox "The script is finished by Hackoo !",VbInformation,"The script is finished by Hackoo !"
Set Ws = CreateObject("wscript.shell")
ws.run "Explorer " & DblQuote(DestinationFolder)
'**************************************************************************
Function Browse4Folder()
Dim objShell,objFolder,Message
Message = "Please select a folder "
Set objShell = CreateObject("Shell.Application")
Set objFolder = objShell.BrowseForFolder(0,Message,0,0)
If objFolder Is Nothing Then
Wscript.Quit
End If
Browse4Folder = objFolder.self.path
End Function
'*********************************************************************
Function Scan4Folder(Folder)
Dim fso,objFolder,File
Dim Tab,aFile,NewFileName
Set fso = CreateObject("Scripting.FileSystemObject")
Set objFolder = fso.GetFolder(Folder)
For Each File in objFolder.Files
NewFileName = GetNewName(File)
If UCase(fso.GetExtensionName(File)) = "XLSX" or UCase(fso.GetExtensionName(File)) = "XLS" Then
Msgbox "The File " & DblQuote(File) & " is copied on " & vbcr &_
DblQuote(DestinationFolder & "\" & NewFileName),vbInformation,DblQuote(File)
fso.CopyFile File,DestinationFolder & "\" & NewFileName
End If
Next
End Function
'*********************************************************************
Sub BuildFullPath(ByVal FullPath)
Dim fso : Set fso = CreateObject("Scripting.FileSystemObject")
If Not fso.FolderExists(FullPath) Then
BuildFullPath fso.GetParentFolderName(FullPath)
fso.CreateFolder FullPath
End If
End Sub
'*********************************************************************
Function DblQuote(Str)
DblQuote = Chr(34) & Str & Chr(34)
End Function
'*********************************************************************
Function GetNewName(sFile)
Dim fso,snamebase,AppendName,Ext
set fso = CreateObject("Scripting.FileSystemObject")
snamebase = Split(Right(sFile, Len(sFile) - InStrRev(sFile,"\")),".")(0)
AppendName = "_Report"
Ext = fso.GetExtensionName(sFile)
GetNewName = snamebase & AppendName & "." & Ext
End Function
'******************************************************************************
答案 1 :(得分:0)