Question

我已从我的Gmail帐户下载了邮件存档。我使用以下从博客中获取的python（2.7）代码将存档的内容转换为csv。

  XX
 X  X
X    X
 X  X
  XX

  XX
 X  X
X    X
X    X
 X  X
  XX

我想要包含邮件正文（实际邮件）......但无法弄清楚如何。我之前没有使用过python，有人可以帮忙吗？我已经使用了其他SO选项，但无法通过。

要执行相同的任务，我也使用了以下代码：但是第60行会出现缩进错误：return json_msg。我尝试了不同的缩进选项，但没有任何改进。

import mailbox
import csv
writer = csv.writer(open(("clean_mail.csv", "wb"))
for message in mailbox.mbox('archive.mbox'):
    writer.writerow([message['subject'], message['from'], message['date']])

Answer 1

试试这个。

import mailbox
import csv
writer = csv.writer(open(("clean_mail.csv", "wb"))
for message in mailbox.mbox('archive.mbox'):
    if message.is_multipart():
        content = ''.join(part.get_payload() for part in message.get_payload())
    else:
        content = message.get_payload()
    writer.writerow([message['subject'], message['from'], message['date'],content])

或者这个：

import mailbox
import csv

def get_message(message):
    if not message.is_multipart():
        return message.get_payload()
    contents = ""
    for msg in message.get_payload():
        contents = contents + str(msg.get_payload()) + '\n'
    return contents

if __name__ == "__main__":

    writer = csv.writer(open("clean_mail.csv", "wb"))
    for message in mailbox.mbox("archive.mbox"):
        contents = get_message(message)
        writer.writerow([message["subject"], message["from"], message["date"],contents])

查找文档here。

Answer 2

Rahul片段对多部分内容的一点改进：

import sys
import mailbox
import csv
from email.header import decode_header

infile = sys.argv[1]
outfile = sys.argv[2]
writer = csv.writer(open(outfile, "w"))


def get_content(part):
    content = ''
    payload = part.get_payload()
    if isinstance(payload, str):
        content += payload
    else:
        for part in payload:
            content += get_content(part)
    return content


writer.writerow(['date', 'from', 'to', 'subject', 'content'])
for index, message in enumerate(mailbox.mbox(infile)):
    content = get_content(message)
    row = [
        message['date'],
        message['from'].strip('>').split('<')[-1],
        message['to'],
        decode_header(message['subject'])[0][0],
        content
    ]
    writer.writerow(row)

使用Python将邮箱发送到csv

2 个答案: