我试图制作一个基本的4函数计算器时遇到此错误。我对c ++相当新,所以可能有更多的错误,但我主要想关注错误,因为我无法编译它。谢谢你的帮助!
#include <iostream>
using namespace std;
float fadd(float num1, float num2, float answ);
float fsub(float num1, float num2, float answ);
float fmul(float num1, float num2, float answ);
float fdiv(float num1, float num2, float answ);
char contOption();
int main()
{
float answ, num1, num2;
char oper, cont;
cout << "Student name: Jose Gomez" << endl;
cout << "Student number: 900724015" << endl << endl << endl;
do
{
cout << "Please enter first number, operator & second number: ";
cin >> num1 >> oper >> num2;
switch (oper)
{
case '+':
fadd(num1, num2, answ); //the 'answ' here is what is giving me the
//error and i do not know how to fix it
cout << endl << "Answer = " << answ;
case '-':
fsub(num1, num2, answ);
cout << endl << "Answer = " << answ;
case '*':
fmul(num1, num2, answ);
cout << endl << "Answer = " << answ;
case '/':
fdiv(num1, num2, answ);
cout << endl << "Answer = " << answ;
default:
cout << "Sorry, illegal operation. Only '+', '-', '*', '/' are allowed" << endl << endl;
cout << "Please enter first number, operator & second number: ";
cin >> num1 >> oper >> num2;
}
cont = contOption();
} while (cont == 'y' || cont == 'Y');
cin.ignore();
cin.get();
return 0;
}
float fadd(float num1, float num2, float answ)
{
answ = num1 + num2;
return answ;
}
float fsub(float num1, float num2, float answ)
{
answ = num1 - num2;
return answ;
}
float fmul(float num1, float num2, float answ)
{
answ = num1*num2;
return answ;
}
float fdiv(float num1, float num2, float answ)
{
answ = num1 / num2;
if (num2 == 0)
cout << "Sorry, divide by 0 is an illegal operation";
else if (num2 != 0)
return answ;
}
char contOption()
{
char cont;
cout << endl << "Would you like to perform another calculation? (y / n): ";
cin >> cont;
return cont;
}
答案 0 :(得分:-1)
首先,您需要初始化变量:
float answ, num1, num2;
answ = num1 = num2 = 0.0;
否则他们是未定义的。其次,你应该在你的switch语句中添加中断,否则你将每次检查每个条件并达到默认条件。
接下来,在您的函数中,您按值而不是通过引用传递参数。这会导致您的函数复制您传入的变量。因此,当您在运行计算后尝试打印答案时,您将尝试打印未初始化的变量。通过引用传递参数实际上将使用您传入的变量。
或者,您可以指定“回复”。如果您希望通过值传递,则从函数返回的值,但是您没有这样做。
这是一个通过引用传递的示例。
#include <iostream>
using namespace std;
void fadd(float& num1, float& num2, float& answ);
void fsub(float& num1, float& num2, float& answ);
void fmul(float& num1, float& num2, float& answ);
void fdiv(float& num1, float& num2, float& answ);
char contOption();
int main()
{
float answ, num1, num2;
answ = num1 = num2 = 0.0;
char oper, cont;
cout << "Student name: Jose Gomez" << endl;
cout << "Student number: 900724015" << endl << endl << endl;
do
{
cout << "Please enter first number, operator & second number: ";
cin >> num1 >> oper >> num2;
switch (oper)
{
case '+':
fadd(num1, num2, answ); //the 'answ' here is what is giving me the
//error and i do not know how to fix it
cout << endl << "Answer = " << answ;
break;
case '-':
fsub(num1, num2, answ);
cout << endl << "Answer = " << answ;
break;
case '*':
fmul(num1, num2, answ);
cout << endl << "Answer = " << answ;
break;
case '/':
fdiv(num1, num2, answ);
cout << endl << "Answer = " << answ;
break;
default:
cout << "Sorry, illegal operation. Only '+', '-', '*', '/' are allowed" << endl << endl;
cout << "Please enter first number, operator & second number: ";
cin >> num1 >> oper >> num2;
}
cont = contOption();
} while (cont == 'y' || cont == 'Y');
cin.ignore();
cin.get();
return 0;
}
void fadd(float& num1, float& num2, float& answ)
{
answ = num1 + num2;
}
void fsub(float& num1, float& num2, float& answ)
{
answ = num1 - num2;
}
void fmul(float& num1, float& num2, float& answ)
{
answ = num1*num2;
}
void fdiv(float& num1, float& num2, float& answ)
{
answ = num1 / num2;
if (num2 == 0)
cout << "Sorry, divide by 0 is an illegal operation";
}
char contOption()
{
char cont;
cout << endl << "Would you like to perform another calculation? (y / n): ";
cin >> cont;
return cont;
}