当某些物体在舞台上时,如何使我的闪存文件仅响应按键?

时间:2015-11-05 01:45:21

标签: flash actionscript-2

我试图在我的flash文件中创建一个对象,仅在屏幕上显示某个对象时才响应键盘。但是,使用我当前的代码(如下),如果按住某个键,它将允许您完成整个程序。我想让它在每次物体进入屏幕时重新按下键。 (程序在as2中)。谢谢!

gyp ERR! build error

gyp ERR! stack Error: `make` failed with exit code: 2

gyp ERR! stack     at ChildProcess.onExit (/usr/local/lib/node_modules/npm/node_modules/node-gyp/lib/build.js:270:23)

gyp ERR! stack     at emitTwo (events.js:87:13)

gyp ERR! stack     at ChildProcess.emit (events.js:172:7)

gyp ERR! stack     at Process.ChildProcess._handle.onexit (internal/child_process.js:200:12)

gyp ERR! System Darwin 14.3.0

gyp ERR! command "/usr/local/bin/node" "/usr/local/lib/node_modules/npm/node_modules/node-gyp/bin/node-gyp.js" "rebuild"

gyp ERR! cwd /Users/afuser/Desktop/wonchan/mean/node_modules/socket.io/node_modules/engine.io/node_modules/ws/node_modules/bufferutil

gyp ERR! node -v v4.2.2

gyp ERR! node-gyp -v v3.0.3

gyp ERR! not ok

npm WARN optional dep failed, continuing utf-8-validate@1.2.1

1 个答案:

答案 0 :(得分:0)

您可以使用简单的select distinct ug.* from table_x x join usergroups ug on x.userId = ug.userId where x.ip_address in ( select x.ip_address from table_x x join usergroups ug on x.userId = ug.userId group by ip_address having count(distinct groupId) > 1) 语句来验证您的对象是否存在:

if

希望可以提供帮助。