Question

看着类似的线程，这并没有显示出来。基本上我希望大厨继承员工（基类）的功能和数据，但是我对派生类的构造函数有疑问。我收到错误：没有匹配函数来调用＆＃39; Employee :: Employee（）＆＃39;有人可以告诉我如何声明我的构造函数以及此程序的未来派生类。尝试了很多东西，似乎无法让它发挥作用。

class Employee
{
    public:
        Employee(int theempID, string thefirstName, string thelastName, char theempClass, int thesalary)
    {
        this->empID = theempID;
        this->firstName = thefirstName;
        this->lastName = thelastName;
        this->empClass = theempClass;
        this->salary = thesalary;
    };


protected:
    int empID;
    string firstName;
    string lastName;
    char empClass;
    int salary;

};


class Chef : public Employee
{
    public:
        Chef(int theempID, string thefirstName, string thelastName, char theempClass, int thesalary, string theempCuisine) : Employee() {}
    {
        this->empID = theempID;
        this->firstName = thefirstName;
        this->lastName = thelastName;
        this->empClass = theempClass;
        this->salary = thesalary;
        this->empCuisine = theempCuisine;
    };

    string getCuisine()
    {
        return empCuisine;
    }

protected:
    string empCuisine;
};



#endif // EMPLOYEE

Answer 1

Employee（）正在尝试默认构造一个Employee，但Employee没有默认构造函数。相反，使用您期望的构造函数构造它。

Chef构造函数应如下所示：

Chef(int theempID, string thefirstName, string thelastName, char theempClass, int thesalary, string theempCuisine) :
    Employee(theempID, thefirstName, thelastName, theempClass, thesalary), empCuisine(theempCuisine)
    {}

注意构造函数的主体是空的。初始化列表中的Employee基类和成员变量是初始化。正文中不需要赋值。您还应该更改基类构造函数，以便它使用初始化而不是赋值。

错误：没有匹配函数来调用＆＃39; Employee :: Employee（）＆＃39;

1 个答案: