我有一个像这样的数组的JSON文件
"vars": [
{
"key": "f1",
"link": "@cooldownchampion",
"coeff": [
24,
23,
22,
21,
20
]
},
{
"key": "f4",
"link": "@text",
"coeff": [
150,
175,
200,
225,
250,
275,
300,
325,
350,
375,
400,
425,
450,
475,
500,
525,
550,
575
]
}
]
我想循环内循环来获取coeff的所有条目
这是我的循环
for (key,subJson):(String, JSON) in newjson["vars"]{
for (key,subJson):(String, JSON) in newjson["vars"][key]["coeff"]{
print (subJson) // this should print 24/23/22/21 but it doesn't
}
}
如您所知,我使用SWIFTYJSON库来处理JSON FILE
答案 0 :(得分:0)
问题是您的第一个key
是String
,并且要按索引访问元素需要Int
。
您可以通过投射来解决问题:
for (key,subJson):(String, JSON) in newjson["vars"] {
for (key,subJson):(String, JSON) in newjson["vars"][Int(key)!]["coeff"]{
print (subJson) // this should print 24/23/22/21 but it doesn't
}
}
但更好的方法是使用现有的JSON对象(subJson
),如下所示:
for (key,subJson):(String, JSON) in newjson["vars"] {
for (key,subJson):(String, JSON) in subJson["coeff"]{
print (subJson) // this should print 24/23/22/21 but it doesn't
}
}
答案 1 :(得分:0)
for (key,subJson):(String, JSON) in newjson["vars"]{
for (key,subJson):(String, JSON) in newjson["vars"][indexInTheArray]["coeff"]{
print (subJson) // this should print 24/23/22/21 but it doesn't
}
}
使用key:String索引数组,indexInTheArray应该是一个整数
答案 2 :(得分:-1)
我不知道如何使用swift进行编码
如果使用object-c
$data = DB::table('workorders')
->select('noworkorder')
->whereYear('date', '=', 2015)
->orderby('noworkorder', 'desc')
->get();