Question

我正在尝试使用Angular的无限滚动模块，并且不知道为什么会出现此错误。

以下是我从chrome控制台复制的错误。

Error: [$injector:unpr] Unknown provider: UploadProvider <- Upload <- MyCtrl
http://errors.angularjs.org/1.4.4/$injector/unpr?p0=UploadProvider%20%3C-%20Upload%20%3C-%20MyCtrl
    at angular.js:68
    at angular.js:4284
    at Object.getService [as get] (angular.js:4432)
    at angular.js:4289
    at getService (angular.js:4432)
    at Object.invoke (angular.js:4464)
    at extend.instance (angular.js:9093)
    at nodeLinkFn (angular.js:8205)
    at compositeLinkFn (angular.js:7637)
    at publicLinkFn (angular.js:7512)

以下是index.html的代码

<body ng-app="fileUpload" ng-controller="MyCtrl">
<div>
    <div infinite-scroll='loadMore()' infinite-scroll-distance="addmore(offer.time_posted)">
        <div ng-repeat="offer in offerlist">{{offer.imageurl}}  {{offer.time_posted}}  {{offer.category}}  {{offer.offercode}}</div>
    </div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.4/angular.js"></script>
<script src="controller13.js"></script>
<script src="ng-infinite-scroll.js"></script>
<script src="ng-infinite-scroll.min.js"></script>

</body>

以下是Angular Controller的代码

var app = angular.module('fileUpload', ['infinite-scroll']);
var imageurl;
var f;
app.controller('MyCtrl', ['$scope', 'Upload', '$timeout','$http', function ($scope, Upload, $timeout, $http) {
    var testttt = '1279';
    var id = '123';
  var refresh = function() {
        $http.get('/fetchtweet', testttt).success(function(response) {
            console.log("I got the data I requested");
            $scope.offerlist = response;
            $scope.offer = "";
        });
    };
    refresh();    
    $scope.addmore = function(time_posted)
    {
        console.log(time_posted);
    };
}]);

Answer 1

app.controller('MyCtrl', ['$scope', 'Upload', '$timeout','$http', function ($scope, Upload, $timeout, $http) {

在上面的陈述中，您正在插入

Upload

作为角度服务。似乎缺少提供者/服务。

Angular - 添加无限滚动模块后的未知提供程序

1 个答案: