Question

我正在尝试提出一个查询，该查询将列出所有task_groups，其中组中的所有task_names由'AUTO'用户执行，除了'Initial'任务将是手动的。因此，对于以下数据，我应该只在结果中看到Task_Group'1'而不是Task_Group'2'

CREATE TABLE [dbo].[QUERY_TST](
    [ID] [int] IDENTITY(1,1) PRIMARY KEY,
    [TASK_GROUP] [int] NOT NULL,
    [TASK_NAME] [varchar](50) NULL,
    [PERFORMED_BY] [varchar](10) NULL
)
--Data
INSERT INTO QUERY_TST VALUES(1, 'INITIAL', 'MANUAL')
INSERT INTO QUERY_TST VALUES(1, 'TASK1', 'AUTO')
INSERT INTO QUERY_TST VALUES(1, 'TASK2', 'AUTO')
INSERT INTO QUERY_TST VALUES(1, 'TASK3', 'AUTO')

INSERT INTO QUERY_TST VALUES(2, 'INITIAL', 'MANUAL')
INSERT INTO QUERY_TST VALUES(2, 'TASK1', 'AUTO')
INSERT INTO QUERY_TST VALUES(2, 'TASK2', 'MANUAL')
INSERT INTO QUERY_TST VALUES(2, 'TASK3', 'AUTO')

Answer 1

这可以让你得到以下的信息：

SELECT DISTINCT
    task_group
FROM query_tst As a
WHERE (
    (NOT EXISTS (
        SELECT NULL
        FROM query_tst As b
        WHERE (
            (a.task_group = b.task_group) And
            (b.task_name <> 'Initial') And
            (b.performed_by <> 'AUTO')
        )
    ))
);

Answer 2

所有任务少于一个由AUTO
初始任务由MANUAL

select [TASK_GROUP]
from [dbo].[QUERY_TST]
GROUP BY [TASK_GROUP]
HAVING SUM(CASE WHEN [PERFORMED_BY] = 'AUTO' AND [TASK_NAME] <> 'Initial' THEN 1 
           ELSE 0 END) = COUNT(*)-1
   AND SUM(CASE WHEN [PERFORMED_BY] = 'MANUAL' AND [TASK_NAME] = 'Initial' THEN 1 
           ELSE 0 END) = 1

Answer 3

你可以这样做：

select *
from query_tst as t1
where 
  TASK_NAME = 'initial'
  and not exists (
   select 1
   from query_tst as t2
   where t1.TASK_GROUP = t2.TASK_GROUP 
   and TASK_NAME <> 'initial'
   and PERFORMED_BY = 'manual'
  )

这是一个显示它工作的小提琴：http://sqlfiddle.com/#!3/f9aa8/5

用于获取除一行之外的所有值匹配的值的SQL查询

3 个答案: