Question

我有一个函数可以检查用户是否在一个库中拥有正确的权限，如果用户有，我希望它设置一个新变量：getprivileges = true

<?php
    $directory = $_SESSION['cwd'];                  // current directory
    $user = $_SESSION['simple_auth']['username'];   // get username
    $repository = gatorconf::get('repository');     // get base repertory of the file manager
    $userdir = $repository.DS.'user'.DS.$user;      // user's repertory

function scanDirectory($userdir = '', $directory){
    $folders = glob($userdir . '/*' , GLOB_ONLYDIR);
    foreach($folders as $folder){
        if (($folder == $directory && gator::checkPermissions('r')) || (gator::checkPermissions('ru')) || ($userdir == $directory && gator::checkPermissions('r'))) {
            $getprivileges = true;
            break;
        }
        scanDirectory($folder, $directory);
    }
}

scanDirectory($userdir, $directory);
?>

<?php if ($getprivileges == true): ?>
<p>Permissions granted.<p>
<?php endif; ?>

我相信功能return正是我想要的，但我真的不知道如何使用它。代码的最后一部分只是我的目标是用我的变量做的例子。

我补充说到目前为止我的变量$ getprivileges没有在我的代码中的任何其他地方定义，所以也许我必须首先给它一个默认值？

有人可以给我一些关于我如何做到这一点的解释吗？

非常感谢

解决方案更新评论：

<?php
    $directory = $_SESSION['cwd'];                  // current directory
    $user = $_SESSION['simple_auth']['username'];   // get username
    $repository = gatorconf::get('repository');     // get base repertory of the file manager
    $userdir = $repository.DS.'user'.DS.$user;      // user's repertory
    $getprivileges = scanDirectory($userdir, $directory);

function scanDirectory($userdir = '', $directory){
    $folders = glob($userdir . '/*' , GLOB_ONLYDIR);
    foreach($folders as $folder){
        if (($folder == $directory && gator::checkPermissions('r')) || (gator::checkPermissions('ru')) || ($userdir == $directory && gator::checkPermissions('r'))) {
            return true;
            break;
        }
        scanDirectory($folder, $directory);
    }
}

scanDirectory($userdir, $directory);
?>

<?php if ($getprivileges == true): ?>
<p>Permissions granted.<p>
<?php endif; ?>

Answer 1

我将其设为社区维基，因为作者已经找到了解决方案。

你是正确的，你需要使用return。通过使用return，您可以返回一些值作为函数调用的值，并将该值赋给变量。在您的情况下，您想要返回true或false。

然后你可以这样设置$getprivileges：

$getprivileges = scanDirectory($userdir, $directory);

你的功能应该是这样的：

function scanDirectory($userdir = '', $directory){
    $folders = glob($userdir . '/*' , GLOB_ONLYDIR);
    foreach($folders as $folder){
        if (($folder == $directory && gator::checkPermissions('r')) || (gator::checkPermissions('ru')) || ($userdir == $directory && gator::checkPermissions('r'))) {
            // Replaced here.
            return true;
        }
        scanDirectory($folder, $directory);
    }

    // Added here.
    return false;
}

使用条件将变量设置为True

1 个答案: