我是C的新手,我正在编写一个代码,用于创建一个包含员工信息数组的结构。正如您在我的代码中所看到的那样,那里有员工(实际上有4名员工,但我在这里将其减少到1名),每名员工都有相应的信息。 (仅仅是因为我省略了一些东西以节省空间,比如声明struct workerT)。
我创建了另一个应该打印所有员工及其信息的功能(prntWorker),但是当我在main()中调用它时,我不知道如何使用perimeter。无论我使用什么周边,CodeBlocks都会返回参数太少。对不起,我知道这是一个新手问题,但我非常感谢任何帮助!
目标是"给定一个包含siz元素的workerT结构数组,打印在数组元素列表中找到的所有员工信息[indx]
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_ROSTER 10 //roster of employees
typedef struct workerT_struct {
char name[81]; //employee name
char title[81]; //employee title
int empID; //unique ID for employee
int empStatus;
int year100_salary; //before-tax salary, in cents
int year100_401k; //annual contribution to retirement, in cents
double taxRate; //fraction used to determine payroll taxes
int month100_paycheck; //monthly paycheck, in cents
} workerT;
void initWorkerArray(workerT list[], int siz);
void prntWorker(workerT list[], int siz, int indx);
int main()
{
workerT roster[MAX_ROSTER];
prntWorker(roster, MAX_ROSTER, 0); //FIXME
return 0;
}
void initWorkerArray(workerT list[], int siz) {
int i = 0;
for (i = 0; i < 4; ++i) {
strcpy(list[0].name, "Buggy, Orson");
strcpy(list[0].title, "Director/President");
list[0].empID = 1;
list[0].empStatus = 1;
list[0].year100_salary = 12015000;
list[0].year100_401k = 950000;
list[0].taxRate = 0.45;
strcpy(list[1].name, "Czechs, Imelda");
strcpy(list[1].title, "Chief Financial Officer");
list[1].empID = 2;
list[1].empStatus = 1;
list[1].year100_salary = 8020000;
list[1].year100_401k = 960000;
list[1].taxRate = 0.39;
strcpy(list[2].name, "Hold, Levon");
strcpy(list[2].title, "Customer Service");
list[2].empID = 6;
list[2].empStatus = -1;
list[2].year100_salary = 8575000;
list[2].year100_401k = 1133000;
list[2].taxRate = 0.39;
strcpy(list[3].name, "Andropov, Picov");
strcpy(list[3].title, "Shipping Coordinator");
list[3].empID = 7;
list[3].empStatus = 1;
list[3].year100_salary = 4450000;
list[3].year100_401k = 375000;
list[3].taxRate = 0.31;
}
for (i = 4; i < siz; ++i) {
strcpy(list[i].name, "none");
strcpy(list[i].title, "none");
list[i].empID = -1;
list[i].empStatus = -1;
list[i].year100_salary = 0;
list[i].year100_401k = 0;
list[i].taxRate = 0.0;
}
return;
}
void prntWorker(workerT list[], int siz, int indx) {
int i = 0;
for (i = 0; i < siz; ++i) {
printf("%s ", list[indx].name);
printf("%s ", list[indx].title);
printf("%d ", list[indx].empID);
printf("%d ", list[indx].empStatus);
printf("%d ", list[indx].year100_salary);
printf("%d ", list[indx].year100_401k);
printf("%lf ", list[indx].taxRate);
printf("%d ", list[indx].month100_paycheck);
}
return;
}
答案 0 :(得分:1)
这是你的调整代码。我主要是从initWorkerArray()
调用main()
,但是删除了它将结构初始化4次的循环。我还更改了循环控制变量,并在打印每条记录后在newline
中添加了prntWorker()
。但是,最后一个字段month100_paycheck
正在打印荒谬的值,因为它尚未计算。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_ROSTER 10 //roster of employees
typedef struct workerT_struct {
char name[81]; //employee name
char title[81]; //employee title
int empID; //unique ID for employee
int empStatus;
int year100_salary; //before-tax salary, in cents
int year100_401k; //annual contribution to retirement, in cents
double taxRate; //fraction used to determine payroll taxes
int month100_paycheck; //monthly paycheck, in cents
} workerT;
void initWorkerArray(workerT list[], int siz);
void prntWorker(workerT list[], int siz, int indx);
int main()
{
workerT roster[MAX_ROSTER];
initWorkerArray(roster, MAX_ROSTER);
prntWorker(roster, MAX_ROSTER, 0); //FIXME
return 0;
}
void initWorkerArray(workerT list[], int siz) {
int i = 0;
strcpy(list[0].name, "Buggy, Orson");
strcpy(list[0].title, "Director/President");
list[0].empID = 1;
list[0].empStatus = 1;
list[0].year100_salary = 12015000;
list[0].year100_401k = 950000;
list[0].taxRate = 0.45;
strcpy(list[1].name, "Czechs, Imelda");
strcpy(list[1].title, "Chief Financial Officer");
list[1].empID = 2;
list[1].empStatus = 1;
list[1].year100_salary = 8020000;
list[1].year100_401k = 960000;
list[1].taxRate = 0.39;
strcpy(list[2].name, "Hold, Levon");
strcpy(list[2].title, "Customer Service");
list[2].empID = 6;
list[2].empStatus = -1;
list[2].year100_salary = 8575000;
list[2].year100_401k = 1133000;
list[2].taxRate = 0.39;
strcpy(list[3].name, "Andropov, Picov");
strcpy(list[3].title, "Shipping Coordinator");
list[3].empID = 7;
list[3].empStatus = 1;
list[3].year100_salary = 4450000;
list[3].year100_401k = 375000;
list[3].taxRate = 0.31;
for (i = 4; i < siz; ++i) {
strcpy(list[i].name, "none");
strcpy(list[i].title, "none");
list[i].empID = -1;
list[i].empStatus = -1;
list[i].year100_salary = 0;
list[i].year100_401k = 0;
list[i].taxRate = 0.0;
}
return;
}
void prntWorker(workerT list[], int siz, int indx) {
int i = 0;
for (i = 0; i < siz; ++i) {
printf("%s ", list[i].name);
printf("%s ", list[i].title);
printf("%d ", list[i].empID);
printf("%d ", list[i].empStatus);
printf("%d ", list[i].year100_salary);
printf("%d ", list[i].year100_401k);
printf("%lf ", list[i].taxRate);
printf("%d ", list[i].month100_paycheck);
printf("\n");
}
return;
}
节目输出:
Buggy, Orson Director/President 1 1 12015000 950000 0.450000 0
Czechs, Imelda Chief Financial Officer 2 1 8020000 960000 0.390000 1636580
Hold, Levon Customer Service 6 -1 8575000 1133000 0.390000 40370720
Andropov, Picov Shipping Coordinator 7 1 4450000 375000 0.310000 -2
none none -1 -1 0 0 0.000000 50397953
none none -1 -1 0 0 0.000000 2047
none none -1 -1 0 0 0.000000 -1
none none -1 -1 0 0 0.000000 5505360
none none -1 -1 0 0 0.000000 43441
none none -1 -1 0 0 0.000000 4222855
答案 1 :(得分:1)
这里有几个问题:
您永远不会调用initWorkerArray
来初始化数组:
int main()
{
workerT roster[MAX_ROSTER];
initWorkerArray(roster, MAX_ROSTER); // add this call
prntWorker(roster, MAX_ROSTER, 0);
return 0;
}
在initWorkerArray
内部,不需要第一个for
循环,因为您正在更新数组中的特定索引。
您永远不会在第二个month100_paycheck
循环或初始字段中初始化for
,因此该字段包含垃圾:
list[0].month100_paycheck = 0;
...
list[1].month100_paycheck = 0;
...
list[2].month100_paycheck = 0;
...
list[3].month100_paycheck = 0;
...
for (i = 4; i < siz; ++i) {
....
list[i].month100_paycheck = 0;
}
然后在prntWorker
中,您没有使用循环索引i
来遍历列表。您正在使用参数indx
,而您实际上并不需要:
void prntWorker(workerT list[], int siz) {
int i = 0;
for (i = 0; i < siz; ++i) {
printf("%s ", list[i].name);
printf("%s ", list[i].title);
printf("%d ", list[i].empID);
printf("%d ", list[i].empStatus);
printf("%d ", list[i].year100_salary);
printf("%d ", list[i].year100_401k);
printf("%lf ", list[i].taxRate);
printf("%d ", list[i].month100_paycheck);
printf("\n"); // put a newline at the end for nicer formatting
}
return;
}
更改此功能后,还可以更改main
中的呼叫:
prntWorker(roster, MAX_ROSTER);
进行这些更改后,您应该获得以下输出:
Buggy, Orson Director/President 1 1 12015000 950000 0.450000 0
Czechs, Imelda Chief Financial Officer 2 1 8020000 960000 0.390000 0
Hold, Levon Customer Service 6 -1 8575000 1133000 0.390000 0
Andropov, Picov Shipping Coordinator 7 1 4450000 375000 0.310000 0
none none -1 -1 0 0 0.000000 0
none none -1 -1 0 0 0.000000 0
none none -1 -1 0 0 0.000000 0
none none -1 -1 0 0 0.000000 0
none none -1 -1 0 0 0.000000 0
none none -1 -1 0 0 0.000000 0