我在d3.js中有一个可折叠的树。我的目标是通过“type”-attribute为节点着色。例如，type =“str”的节点应填充红色，而type =“elem”的节点应涂成绿色。我无法让它发挥作用。有人可以帮帮我吗。
这是我的代码：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Tree Collapsible Example</title>
<style>
.node {
cursor: pointer;
}
.node circle {
fill: #fff;
stroke: steelblue;
stroke-width: 2px;
}
.node text {
font: 10px sans-serif;
}
.link {
fill: none;
stroke: #ccc;
stroke-width: 1.5px;
}
</style>
</head>
<body>
<!-- load the d3.js library -->
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
// ************** Generate the tree diagram *****************
var margin = {top: 20, right: 120, bottom: 20, left: 120},
width = 1000 - margin.right - margin.left,
height = 500 - margin.top - margin.bottom;
var i = 0,
duration = 750,
root;
var tree = d3.layout.tree()
.size([height, width]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var svg = d3.select("body").append("svg")
.attr("width", width + margin.right + margin.left)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
// load the external data
d3.json("dendrogram02.json", function(error, treeData) {
root = treeData[0];
root.x0 = height / 2;
root.y0 = 0;
update(root);
});
d3.select(self.frameElement).style("height", "500px");
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
links = tree.links(nodes);
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 80; });
// Update the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", click);
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeEnter.append("text")
.attr("x", function(d) { return d.children || d._children ? 20 : 13; })
.attr("dy", function(d) { return d.children || d._children ? "-.8em" : ".35em"; })
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", 4)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.select("circle")
.attr("r", 1e-6);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = svg.selectAll("path.link")
.data(links, function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
});
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
}
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}
</script>
</body>
</html>
和相应的.json：
[
{
"name": "1",
"type": "sources",
"children": [
{
"name": "0",
"type": "dfasdl",
"children": [
{
"name": "companies",
"type": "seq",
"children": [
{
"name": "row",
"type": "elem",
"children": [
{
"name": "id",
"type": "str"
},
{
"name": "companyName",
"type": "str"
},
{
"name": "industry",
"type": "str"
},
{
"name": "telephoneCompany",
"type": "str"
},
{
"name": "date_entered",
"type": "datetime"
}
]
}
]
},
{
"name": "contacts",
"type": "seq",
"children": [
{
"name": "row",
"type": "elem",
"children": [
{
"name": "id",
"type": "str"
},
{
"name": "title",
"type": "str"
},
{
"name": "contactFirstName",
"type": "str"
},
{
"name": "contactLastName",
"type": "str"
},
{
"name": "telephoneUS",
"type": "str"
}
]
}
]
},
{
"name": "employees",
"type": "seq",
"children": [
{
"name": "row",
"type": "elem",
"children": [
{
"name": "id",
"type": "str"
},
{
"name": "position",
"type": "str"
},
{
"name": "employeeFirstName",
"type": "str"
},
{
"name": "employeeLastName",
"type": "str"
},
{
"name": "telephoneUS",
"type": "str"
}
]
}
]
},
{
"name": "vendors",
"type": "seq",
"children": [
{
"name": "row",
"type": "elem",
"children": [
{
"name": "id",
"type": "str"
},
{
"name": "type",
"type": "str"
},
{
"name": "vendorFirstName",
"type": "str"
},
{
"name": "vendorLastName",
"type": "str"
},
{
"name": "telephone",
"type": "str"
}
]
}
]
}
]
}
]
}
]
答案 0 :(得分：5)
您需要做的就是修改
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
根据您的要求：
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) {
if(d.type == "str") return "red";
if(d.type == "elem") return "green";
});
当您将填充色设置两次时，您还必须为更新选择执行此操作：
nodeUpdate.select("circle")
.attr("r", 4)
.style("fill", function(d) {
if(d.type == "str") return "red";
if(d.type == "elem") return "green";
});