Question

我应该如何恰当地关闭毕加索？

实施例：我只有1个活动，在onDestroy中的这个活动中，我在所有picasso实例上调用shutdown（）（我不使用单例实例）。但是，在此活动被破坏之前，毕加索正在让设备保持清醒状态（我启动应用程序，使用它，按下主页，单独留下手机，周一检查，电池坏了，因为毕加索保持手机清醒）

这些Picasso线程仍在运行：

-Picasso-统计

-Picasso-refQue（两次）

-Picasso-Dispatcher（两次）

为什么呢？他们应该这样做吗？

关闭它的最佳做法是什么？在onStop（）？我应该保留一份未完成的下载列表，我可能想在onResume（）中重试？

Answer 1

据我所知，picasso中的默认单例实例无法关闭，

但我解决了问题，在picasso.java＆＃39;文件在线：643

找到了这段代码：

@Override public void run() {
  Process.setThreadPriority(THREAD_PRIORITY_BACKGROUND);
  while (true) {
    try {
      // Prior to Android 5.0, even when there is no local variable, the result from
      // remove() & obtainMessage() is kept as a stack local variable.
      // We're forcing this reference to be cleared and replaced by looping every second
      // when there is nothing to do.
      // This behavior has been tested and reproduced with heap dumps.
      RequestWeakReference<?> remove =
          (RequestWeakReference<?>) referenceQueue.remove(THREAD_LEAK_CLEANING_MS);
      Message message = handler.obtainMessage();
      if (remove != null) {
        message.what = REQUEST_GCED;
        message.obj = remove.action;
        handler.sendMessage(message);
      } else {
        message.recycle();
      }    
    } catch (InterruptedException e) {
      break;
    } catch (final Exception e) {
      handler.post(new Runnable() {
        @Override public void run() {
          throw new RuntimeException(e);
        }
      });
      break;
    }
  }
}

虽然（true）有高CPU使用率，我决定按如下方式更改它：

@Override public void run() {
  Process.setThreadPriority(THREAD_PRIORITY_BACKGROUND);
  while (true) {
    try {
      // Prior to Android 5.0, even when there is no local variable, the result from
      // remove() & obtainMessage() is kept as a stack local variable.
      // We're forcing this reference to be cleared and replaced by looping every second
      // when there is nothing to do.
      // This behavior has been tested and reproduced with heap dumps.
      RequestWeakReference<?> remove =
          (RequestWeakReference<?>) referenceQueue.remove(THREAD_LEAK_CLEANING_MS);
      Message message = handler.obtainMessage();
      if (remove != null) {
        message.what = REQUEST_GCED;
        message.obj = remove.action;
        handler.sendMessage(message);
      } else {
        message.recycle();
      }

      Thread.sleep(2000);//===> call ever 2 sec to decrease cpu pressure.

    } catch (InterruptedException e) {
      break;
    } catch (final Exception e) {
      handler.post(new Runnable() {
        @Override public void run() {
          throw new RuntimeException(e);
        }
      });
      break;
    }
  }
}

毕加索线程继续运行

1 个答案: