Question

create table imsi_data(account varchar2(20)not null,imsi number(10),seqno number(20) not null,package_id number(10),event_date date)

insert into imsi_data values('10001',123456,09,164,add_months((sysdate),-2));
insert into imsi_data values('10001',123456,09,164,add_months((sysdate-1),-2));
insert into imsi_data values('10001',123456,09,164,add_months((sysdate-2),-2));
insert into imsi_data values('10001',123456,10,165,add_months((sysdate),-1));
insert into imsi_data values('10001',123456,10,165,add_months((sysdate-1),-1));
insert into imsi_data values('10001',123456,10,165,add_months((sysdate-2),-1));

select * from imsi_data

ACCOUNT IMSI    SEQNO   PACKAGE_ID  EVENT_DATE       

1   10001   123456    9      164       9/4/2015 4:17:06 AM  
2   10001   123456    9      164       9/3/2015 4:17:18 AM  
3   10001   123456    9      164       9/2/2015 4:18:16 AM  
4   10001   123456   10      165      10/4/2015 4:18:34 AM  
5   10001   123456   10      165      10/3/2015 4:23:23 AM  
6   10001   123456   10      165      10/2/2015 4:23:31 AM

预期产量：我需要在一行中查看数据，获取最新的seq没有详细信息和lastusagedate（如上一个seqno（9）最新日期）

ACCOUNT IMSI  SEQNO   PACKAGEID  LastUsageDate        CurrentUsageDate 

10001   123456 10       165     9/4/2015 4:17:06 AM    10/4/2015 4:18:34 AM

我的sql在这里：

select account,
       imsi,
       lastusage_date,
       current_date,
       package_id,
       seqno
from (
   select ce.package_id,
          ce.seqno,
          ce.account,
          ce.IMSI,
          lag(ce.event_date) over(partition by ce.IMSI, ce.seqno order by ce.IMSI, ce.event_date desc) lastusage_date,
          ce.event_date current_date,
          row_number() over(partition by ce.imsi, ce.seqno order by ce.event_date desc) rn
   from imsi_data ce
    where ce.account = '10001' and ce.seqno in (10, 09)
    group by ce.account, ce.seqno, ce.imsi, ce.event_date, ce.package_id)
where rn =1

这使得lastusagedate为null。但是我应该得到之前的seq max event_date，任何人都可以帮助我：

Answer 1

您可以尝试以下操作：

select
    ce.account,
    ce.IMSI,
    ce.seqno,
    ce.package_id,
    (
      select 
          max(prev_seq_date_ivw.event_date) ev_date 
        from 
          imsi_data prev_seq_date_ivw 
        where 
          prev_seq_date_ivw.seqno = (
            select 
                max(prev_seq_ivw.seqno) 
              from 
                imsi_data prev_seq_ivw 
              where 
                prev_seq_ivw.seqno < ce.seqno
          )
    ) last_usage_date,
    max(ce.event_date) current_usage_date
  from imsi_data ce
  where ce.account = '10001' and ce.seqno in (10, 09)
  group by     
    ce.account,
    ce.IMSI,
    ce.seqno,
    ce.package_id;

如何在sql中检索上个月的最新日期和当前月份的最新日期

1 个答案: